打印10 x 10坐標網格

Question

我正在打印一個從0-9的列和0-9的行顯示的網格。

我想將其顯示為0-9的列和A-J的行，但是不確定如何在循環中使用字符而不是Integer？

public class BattleshipGame {

private char[][] playerBoard;   
private char[][] compBoard;     
private final static int boardSize = 10;
private String input, shipType, shipDirection = ""; 
public static String name;      
private int shipRowLoc, shipColLoc; 
private boolean allowed, random = false, showShips = false;
private MoveType moveType;
private ArrayList<Battleships> enemyShips = new ArrayList<Battleships>();

Scanner userinput = new Scanner(System.in);

public BattleshipGame() {
    playerBoard = new char[boardSize][boardSize];
    compBoard = new char[boardSize][boardSize];
    initializeBoard();  
    placeShip();    
}

public void initializeBoard() {
    for (int i = 0; i < boardSize; i++)
        for (int j = 0; j < boardSize; j++){
            playerBoard[i][j] = '~';
            compBoard[i][j] = '~';
    }
}

Answer 1

您有幾種選擇，可以使用

for (char ch = 'A'; ch <= 'J'; ch++)

或類似的東西

for (int j = 0; j < 10; j++) {
  char ch = (char) ('A' + j);

Answer 2

要從int映射字符A - J ，您可能只需在它們的代碼點索引它們即可。

例如， A為65 。

因此System.out.println((char)65)將打印A

將其從0到9遞增索引，您將得到從A到J字符。