[英]haskell case that calls a function
我已經待了很長時間了,我想不出什么錯Haskell只是讓我感到自己很笨
data Operation
= Nth Integer
fib :: (Integral i, Integral j) => i -> j
fib n | n == 0 = 1
| n == 1 = 1
| n == 2 = 1
| n == 3 = 1
| otherwise = (fib(n-1)+fib(n-2))* fib(n-3) `div` fib(n-4)
main = do
command <- getLine
case command of
Nth op -> show $ fib op
Nothing -> "Invalid operation"
因此,當用戶輸入Nth 9時,需要使用n = 9調用fib函數並將輸出提供給用戶。 我覺得我的案例控制結構合適,但我根本無法使它正常工作!!!
你快完成了。 使用deriving (Read)
讀取String
作為Operation
。 http://en.wikibooks.org/wiki/Haskell/Classes_and_types#Deriving
如果要處理讀取錯誤,請參見如何從Haskell的讀取函數中捕獲無解析異常?
data Operation = Nth Integer deriving (Read)
fib :: (Integral i, Integral j) => i -> j
fib n | n == 0 = 1
| n == 1 = 1
| n == 2 = 1
| n == 3 = 1
| otherwise = (fib(n-1)+fib(n-2))* fib(n-3) `div` fib(n-4)
main = do
command <- getLine
print $ case read command of
Nth op -> fib op
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