如何跟蹤python中while循環的輸入數量？

Question

我正在嘗試用python創建一個“數字猜謎游戲”，並且我希望它顯示用戶為猜測最后由計算機生成的隨機數而必須進行的猜測的數目。 到目前為止，這里是我所要表達的示例：

    from random import*
a=randrange(1,51)
b=int(input("Can you guess my number?: "))
while a>b:
    b=int(input("Too low, try again: "))
while a<b:
    b=int(input("Too high, try again: "))
while a==b:
    print("You got it! The number was", a)
    break

我希望它在最后打印類似“花了您__個猜測”的內容。 我將如何跟蹤這樣的輸入數量？ 我嘗試四處搜尋，但是我不確定如何將它寫成文字。

Answer 1

您想要做的是擺脫3個while循環，並將它們更改為while循環內的if語句：

from random import*
a=randrange(1,51)
b = 0
guesses = 0 #Initialize a variable to store how many guesses the user has used
while b != a:
    b=int(input("Can you guess my number?: "))
    if a>b:
        b=int(input("Too low, try again: "))
    else:
        b=int(input("Too high, try again: "))
    guesses+=1

print("You got it! The number was", a)
print("You took {} guesses!".format(guesses))

Answer 2

猜測保持否。 猜測

from random import*

a=randrange(1,51)
guess = 0
while True:
    b=int(input("Can you guess my number?: "))
    guess += 1

    if b==a:
        print("You got it correct")
        break

    elif b>a:
        print("number is higher")

    else:
        print("number is lower")

print("Guesses: ", guess)

Answer 3

d = 74計數= 1

def check(n): if n==d: count += 1 print "You Got the number" elif n>d:
print "The number is too high" count += 1 check(int(raw_input('Enter another number'))) elif n<d:
print "The no is too low" if count count += 1 check(int(raw_input('Enter something high'))) return count

返回的值是猜測數