如何跟踪python中while循环的输入数量？

Question

I'm trying to make a "number guessing game" in python, and I want it to display the number of guesses the user had to make in order to guess the random number generated by the computer at the end. Here's what I have so far to give an example of what I mean:

    from random import*
a=randrange(1,51)
b=int(input("Can you guess my number?: "))
while a>b:
    b=int(input("Too low, try again: "))
while a<b:
    b=int(input("Too high, try again: "))
while a==b:
    print("You got it! The number was", a)
    break

I'd like it to print something like "it took you __ guesses" at the end. How would I go about keeping track of the number of inputs like that? I tried searching around, but I wasn't really sure how to put it into words.

Answer 1

What you want to do is get rid of the 3 while loops, and change them to if statements within a while loop:

from random import*
a=randrange(1,51)
b = 0
guesses = 0 #Initialize a variable to store how many guesses the user has used
while b != a:
    b=int(input("Can you guess my number?: "))
    if a>b:
        b=int(input("Too low, try again: "))
    else:
        b=int(input("Too high, try again: "))
    guesses+=1

print("You got it! The number was", a)
print("You took {} guesses!".format(guesses))

Answer 2

guess keeps track of no. of guesses

from random import*

a=randrange(1,51)
guess = 0
while True:
    b=int(input("Can you guess my number?: "))
    guess += 1

    if b==a:
        print("You got it correct")
        break

    elif b>a:
        print("number is higher")

    else:
        print("number is lower")

print("Guesses: ", guess)

Answer 3

d = 74 count = 1

def check(n): if n==d: count += 1 print "You Got the number" elif n>d:
print "The number is too high" count += 1 check(int(raw_input('Enter another number'))) elif n<d:
print "The no is too low" if count count += 1 check(int(raw_input('Enter something high'))) return count

The value returned is the number of guesses