簡體   English   中英

不同的ListView項目啟動不同的彈出

[英]Different ListView item Launch Different Flyout

我正在尋找一種方法,以根據變量Type的值為不同的ListViewItem啟動不同的Flyout,並且當前轉換器無法正常工作。

假設我有1個Converter,2個Flayouts和1個DataTemplate。

<Page.Resources>
    <common:TypeToFlyoutTypeConverter x:Key="typeToFlyoutConverter"/>
    <Flyout x:Name="FlyoutTemplateConfirmed">
        <Grid >
            <TextBlock Text="Confirmed"/>
        </Grid>
    </Flyout>
    <Flyout x:Name="FlyoutTemplateRejected">
        <Grid >
            <TextBlock Text="Rejected"/>
        </Grid>
    </Flyout>
    <DataTemplate x:Key="ListViewItemTemplate">
        <Grid Tapped="Grid_Tapped" 
              FlyoutBase.AttachedFlyout="{Binding Type, Converter={StaticResource typeToFlyoutConverter}}">
        </Grid>
    </DataTemplate>
</Page.Resources>

而轉換器:

public class TypeToFlyoutTypeConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, string language)
    {
        if ((value as String).Contains("TypeConfirmed"))
            return "StaticResource FlyoutTemplateConfirmed";
        else
            return "StaticResource FlyoutTemplateRejected";
    }

    public object ConvertBack(object value, Type targetType, object parameter, string language)
    {
        throw new NotSupportedException();
    }
}

和ListView:

<ListView
    SelectionMode="None" IsItemClickEnabled="True" IsSwipeEnabled="false"
    ItemTemplate="{StaticResource ListViewItemTemplate}"
    ItemsSource="{Binding}">
</ListView>

Grid_Tapped事件處理程序:

private void Grid_Tapped(object sender, TappedRoutedEventArgs e)
{
    FrameworkElement element = sender as FrameworkElement;
    if (element != null)
    {
        FlyoutBase.ShowAttachedFlyout(sender as FrameworkElement);
    }
}

是否可以根據Type的值啟動不同的Flyout?

謝謝!

你可以使用基於類型的多態

public object ShowAttachedFlyout(FrameworkElement t)
{

}
public object ShowAttachedFlyout( OtherspecificTYpe o)
{

}

然后用動態調用

FlyoutBase.ShowAttachedFlyout((dynamic)sender);

在徘徊了幾個小時的stackoverflow之后,我有了一個很好的主意來解決這個問題

我不使用轉換器,而是定義要附加的彈出Grid_Tapped並在Grid_TappedGrid_Tapped編程方式顯示它:

    private void Grid_Tapped(object sender, TappedRoutedEventArgs e)
    {
        string itemType = ((sender as Grid).DataContext as blabla).Type;

        if (itemType.Contains("blibli") && (sender as FrameworkElement) != null)            
            FlyoutBase.SetAttachedFlyout(sender as FrameworkElement, (Flyout)this.Resources["FlyoutTemplateConfirmed"]);
        else if ((sender as FrameworkElement) != null)            
            FlyoutBase.SetAttachedFlyout(sender as FrameworkElement, (Flyout)this.Resources["FlyoutTemplateRejected"]);

        FlyoutBase.ShowAttachedFlyout(sender as FrameworkElement);
    }

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM