繞過多維數組

Question

我需要從復雜數組中獲取一些數據。 例如，我有這個結構：

animals =
     /*...*/
         list: [
           {
             type: "fluffy"
             withCategories: false
             animal: [
               {
                 name: "Patrik"
                 description: "..."
                 price: 135
                 weight: 220
                 rating: 94
               }
               {
                 name: "Mike"
                 description: "..."
                 price: 135
                 weight: 235
                 rating: 97
               }
             ]
           }
           {
             imageUrl: "/img/borsh.jpg"
             type: "pets"
             withCategories: true
             categories: [
               {
                 name: "parrot"
                 imageUrl: "/img/parrot.jpg"
                 withCategories: false
                 animal: [
                   {
                     name: "Kesha"
                     description: "..."
                     price: 75
                     weight: 250
                     rating: 89
                   }
                 ]
               }
             ]
           }

結果，我需要一個包含動物元素的數組： //結果= [object1->名稱：Patrik，價格：135 ..]，...，[object3->名稱：Kesha，描述：...]您可以在較低的級別看到如果參數“ withCategories” = true，我們將遞歸下降。 我試圖實現它：

PlacesService.getAllAnimals = ->
    merged = []
    temp = (getAnimalByCategory(category) for category in animals.list)
    merged = merged.concat.apply(merged, temp)
    return merged

  getAnimalByCategory = (category) ->
    if category.withCategories == false
      return category.animal
    else
      (getAnimalByCategory(an) for an in category.categories)

但是出了點問題：（有人可以幫我嗎？我找不到任何錯誤。

Answer 1

您希望您的getAnimalByCategory返回一個平面列表，以便可以由concat合並循環的結果。 但是，在遞歸情況下，您不會返回此類。

PlacesService.getAllAnimals = ->
  [].concat.apply([], getAnimalByCategory(category) for category in animals.list)

getAnimalByCategory = (category) ->
  if not category.withCategories
    category.animal
  else
    [].concat.apply([], getAnimalByCategory(an) for an in category.categories)