輸出多維數組

Question

我目前有以下數組設置：

var TicketInfo =
    {
        t1: {
            1: [7, 12, 35,39,41, 43],
            2: [7, 15, 20,34,45, 48],
            3: [3, 7, 10, 13, 22, 43],
            4: [2, 4, 5,23,27, 33]
        },
        t2: {
            1: [10, 12, 17,44,48, 49],
            2: [13, 15, 17, 18, 32, 39],
            3: [16, 17, 20, 45, 48, 49],
            4: [6, 16, 18, 21, 32, 40]
        }
        }

我想要做的是遍歷這些，以將陣列重新帶回到下面。

作為測試，我嘗試了以下方法：

for(t in TicketInfo["t1"])
{
    i++;
        Write(t.i);
}

但這顯然不符合我的要求。

有任何想法嗎？

我希望能夠輸出像[7, 12, 35,39,41, 43]這樣的數組

謝謝

Answer 1

var TicketInfo =
{
    t1: {
        1: [7, 12, 35,39,41, 43],
        2: [7, 15, 20,34,45, 48],
        3: [3, 7, 10, 13, 22, 43],
        4: [2, 4, 5,23,27, 33]
    },
    t2: {
        1: [10, 12, 17,44,48, 49],
        2: [13, 15, 17, 18, 32, 39],
        3: [16, 17, 20, 45, 48, 49],
        4: [6, 16, 18, 21, 32, 40]
    }
}

for(var j in TicketInfo )
{
    for(var p in TicketInfo[j] )
    {
        for(var i = 0; i < TicketInfo[j][p].length; i++ )
        {
             console.log(TicketInfo[j][p][i]);
        }
    }
}​

http://jsfiddle.net/J6rTj/

Answer 2

如果您是Google來這里的人，試圖找到一種快速打印調試的方法，那么這里有一條線供您選擇：

console.log(myArray.join("\n"))

例：

var myArray = [[1,2,3],[4,5,6],[7,8,9]];
console.log(myArray.join("\n"));

輸出：

1,2,3
4,5,6
7,8,9

帶有適當括號的示例：

var myArray = [[1,2,3],[4,5,6],[7,8,9]];
console.log("[[" + myArray.join("],\n[") + "]]");

輸出：

[[1,2,3],
[4,5,6],
[7,8,9]]

回答OP的問題：

obj =  {
    1: [7, 12, 35,39,41, 43],
    2: [7, 15, 20,34,45, 48],
    3: [3, 7, 10, 13, 22, 43],
    4: [2, 4, 5,23,27, 33],
}
var keys = Object.keys(obj);
keys.sort();
console.log(keys);
var listFromObj = []
for (var i = 0; i < keys.length; i++) {
    if (obj.hasOwnProperty(keys[i])) listFromObj.push(obj[keys[i]]);
}
console.log("[" + listFromObj.join("]\n[") + "]");

輸出：

[7,12,35,39,41,43]
[7,15,20,34,45,48]
[3,7,10,13,22,43]
[2,4,5,23,27,33]

Answer 3

語法為TicketInfo["t1"]["1"][0] 。

該示例將給您7 。

TicketInfo["t1"]["1"]將為您提供問題依據的數組。

Answer 4

在您的代碼中， t僅表示密鑰。

嘗試以下代碼：

var TicketInfo =
    {
        t1: {
            1: [7, 12, 35,39,41, 43],
            2: [7, 15, 20,34,45, 48],
            3: [3, 7, 10, 13, 22, 43],
            4: [2, 4, 5,23,27, 33]
        },
        t2: {
            1: [10, 12, 17,44,48, 49],
            2: [13, 15, 17, 18, 32, 39],
            3: [16, 17, 20, 45, 48, 49],
            4: [6, 16, 18, 21, 32, 40]
        }
}

for(t in TicketInfo["t1"])
{
    i++;
        console.log(TicketInfo["t1"][t]);
}

Answer 5

我知道您要按順序輸出整個表嗎？ 由於您使用的是t1 / t2級別的對象，因此您必須為此執行額外的步驟。

首先，看看您是否可以簡單地用實數組替換對象：

var TicketInfoArrays = {
    t1: [
        [7, 12, 35,39,41, 43],
        [7, 15, 20,34,45, 48],
        [3, 7, 10, 13, 22, 43],
        [2, 4, 5,23,27, 33]
    ]
}


var t1 = TicketInfoArrays.t1

for(var idx = 0, len = t1.length; idx<len; idx++){
    var line = idx+": ["
    var nested = t1[idx]
    for(var idx2 = 0, len2 = nested.length; idx2<len2; idx2++){
        line += ((idx2 > 0 ? ', ':'') + nested[idx2])
    }
    console.log(line + ']')
}

如果這是不可能的，但是您可以確保這些對象中的鍵始終以某個特定的數字開始並且無間隙地遞增，則可以簡單地遍歷屬性，直到遇到空元素：

var TicketInfo = {
    t1: {
        1: [7, 12, 35,39,41, 43],
        2: [7, 15, 20,34,45, 48],
        3: [3, 7, 10, 13, 22, 43],
        4: [2, 4, 5,23,27, 33]
    }
}

var t1 =  TicketInfo.t1

var idx = 1
var nested
while(nested = t1[idx]){
    var line = idx+": ["
    var nested = t1[idx]
    for(var idx2 = 0, len2 = nested.length; idx2<len2; idx2++){
        line += ((idx2 > 0 ? ', ':'') + nested[idx2])
    }
    console.log(line + ']')
    idx++
}

最后，如果甚至不能保證，您將必須手動收集所有鍵，對它們進行排序，然后遍歷此排序列表。

var TicketInfoUnordered = {
    t1: {
        8: [7, 12, 35,39,41, 43],
        20: [7, 15, 20,34,45, 48],
        45: [3, 7, 10, 13, 22, 43],
        3: [2, 4, 5,23,27, 33]
    }
}

var t1 = TicketInfoUnordered.t1

var keys = []
for(key in t1){
    if(t1.hasOwnProperty(key)){ keys.push(key) }
}
keys.sort(function(a, b){ return a - b })

for(var idx = 0, len = keys.length; idx<len; idx++){
    var line = keys[idx]+": ["
    var nested = t1[keys[idx]]
    for(var idx2 = 0, len2 = nested.length; idx2<len2; idx2++){
        line += ((idx2 > 0 ? ', ':'') + nested[idx2])
    }
    console.log(line + ']')
}