[英]How to add characters to filename using glob in Python?
以下是一段代碼。 該腳本從“Test”文件夾中獲取輸入文件,運行一個函數,然后在“Results”文件夾中輸出具有相同名稱的文件(即"Example_Layer.shp")
。 我怎么能設置它,以便輸出文件改為"Example_Layer(A).shp"
?
#Set paths
path_dir = home + "\Desktop\Test\\"
path_res = path_dir + "Results\\"
def run():
#Set definitions
input = path_res + "/" + "input.shp"
output = path_res + "/" + fname
#Set current path to path_dir and search for only .shp files then run function
os.chdir(path_dir)
for fname in glob.glob("*.shp"):
run_function, input, output
run()
您當前計算output
變量一次(由於您尚未定義任何fname
,因此IMO將無效)。
在for循環中移動計算輸出變量的語句,如下所示:
#Set paths
path_dir = home + "\Desktop\Test\\"
path_res = path_dir + "Results\\"
def run():
#Set definitions
input = path_res + "/" + "input.shp"
#Set current path to path_dir and search for only .shp files then run function
os.chdir(path_dir)
for fname in glob.glob("*.shp"):
output = path_res + "/" + fname
run_function, input, output
run()
回答你的問題:
我怎么能設置它,以便輸出文件改為“Example_Layer(A).shp”
您可以使用shutil.copy將文件復制到新目錄,使用os.path.join
為每個文件名添加"(A)"
以加入路徑和新文件名:
path_dir = home + "\Desktop\Test\\"
path_res = path_dir + "Results\\"
import os
import shutil
def run():
os.chdir(path_dir)
for fname in glob.glob("*.shp"):
name,ex = fname.rsplit(".",1) # split on "." to rejoin later adding a ("A")
# use shutil.copy to copy the file after adding ("A")
shutil.copy(fname,os.path.join(path_res,"{}{}{}".format(name,"(A)",ex)))
# to move and rename in one step
#shutil.move(fname,os.path.join(path_res,"{}{}{}".format(name,"(A)",ex)))
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