[英]Select a value in drop-down automatically based on controller in codeigniter?
[英]MySQL Select based on drop down value
我有以下代碼:
<?php
session_start();
include_once("config.php");
$query = "SELECT Category FROM books";
$result = mysqli_query ($mysqli, $query);
echo '<select name="dropdown" value=""><option value="">Dropdown</option>';
while($row = mysqli_fetch_array($result))
{
echo '<option value="' . $row['Category'] . '">' . $row['Category'] . '</option>';
}
echo "</select>";
?>
下拉框的值從數據庫填充。 我想知道是否有一種方法可以使select語句在用戶單擊下拉菜單中的一個選項然后將結果填充到表中時運行?
任何信息都會有所幫助!
謝謝
我假設$ mysqli是您的數據庫連接,它是通過config.php建立的。 我還假設類別是books表中的列名。 您需要清理和驗證用戶輸入。 這只是一個入門的示例。
page.php ....
<?php
session_start();
include_once("config.php");
function categories() {
global $mysqli;
$result = "";
$stmt = "SELECT Category FROM books GROUP BY Category";
$sql = mysqli_query ($mysqli, $stmt);
while ($row = $sql->fetch_array(MYSQLI_BOTH))
{
$result .= '<option value="' . $row['Category'] . '">' . $row['Category'] . '</option>';
}
mysqli_free_result($sql);
mysqli_close($mysqli);
return $result;
}
IF (isset($_POST['ThisForm'])) {
$category = htmlspecialchars(strip_tags(trim($_post['dropdown'])));
$stmt = "SELECT * FROM books WHERE category ='$category'";
$sql = mysqli_query ($mysqli, $stmt);
while ($row = $sql->fetch_array(MYSQLI_BOTH))
{
// do something with result
}
// free result and close connection
mysqli_free_result($sql);
mysqli_close($mysqli);
}ELSE{
// base form
echo '<form action="page.php" name="something" method="post">';
echo '<select name="dropdown" value=""><option value="">Dropdown</option>'.categories().'</select>';
echo '<input type="submit" name="ThisForm" value="submit" />';
echo '<form>';
}
?>
好的,resontant81,您想根據選擇的選項來填充表格,下一個代碼完全符合您的要求,解釋如下:
<html>
<head>
<title>My list</title>
<script type="text/javascript">
//----------------------------------------------------------------
// SENDS SELECTED OPTION TO RETRIEVE DATA TO FILL TABLE.
function send_option () {
var sel = document.getElementById( "my_select" );
var txt = document.getElementById( "my_option" );
txt.value = sel.options[ sel.selectedIndex ].value;
var frm = document.getElementById( "my_form" );
frm.submit();
}
//----------------------------------------------------------------
</script>
</head>
<body>
Click on any option
<br/>
<select id="my_select" onchange="send_option();">
<option>Select an option</option>
<?php
//----------------------------------------------------------------
// LIST FILLED FROM DATABASE (ALLEGEDLY).
for ( $i = 0; $i < 5; $i++ )
{ $text = chr($i+65) . chr($i+65) . chr($i+65);
echo "<option value='" . $text . "'>" . $text . "</option>";
}
//----------------------------------------------------------------
?>
</select>
<br/>
<br/>
<table>
<?php
//----------------------------------------------------------------
// TABLE FILLED FROM DATABASE ACCORDING TO SELECTED OPTION.
if ( IsSet( $_POST["my_option"] ) ) // IF USER SELECTED ANY OPTION.
for ( $i = 0; $i < 4; $i++ ) // DISPLAY ROWS.
{ echo "<tr>";
for ( $j = 0; $j < 6; $j++ ) // DISPLAY COLUMNS.
echo "<td>" . $_POST["my_option"] . "</td>"; // DISPLAY OPTION.
echo "</tr>";
}
else echo "<tr><td>Table empty</td></tr>";
//----------------------------------------------------------------
?>
</table>
<!-- FORM TO SEND THE SELECTED OPTION. -->
<form method="post" action"01.php" style="display:none" id="my_form">
<input type="text" id="my_option" name="my_option"/>
</form>
</body>
</html>
為了使您(和我)更輕松,我沒有使用數據庫,您要做的就是將先前的代碼復制粘貼到文本文件中,將其重命名為“ 01.php”(因為這是表單的作用) ,您可以對其進行更改),然后即可在瀏覽器中運行它。
下拉列表從數據庫填充(在本例中為字母),選擇了某個選項后,頁面將使用所選選項重新加載並填充表格。
您說:“一條選擇語句,當用戶單擊下拉菜單中的一個選項,然后將結果填充到表中時,將運行該選擇語句”。 您想要的以下select語句必須放在以下行之后:
if ( IsSet( $_POST["my_option"] ) ) // IF USER SELECTED ANY OPTION.
因此,您的select語句將從$ _POST中獲取選定的選項,並使用它來檢索正確的數據並顯示它。
讓我知道是否有幫助。
這是填充下拉列表的代碼,這是我的代碼與您的代碼的總和:
// LIST FILLED FROM DATABASE (ALLEGEDLY).
$query = "SELECT Category FROM books";
$result = mysqli_query ($mysqli, $query);
while ( $row = mysqli_fetch_array($result) )
echo "<option value='" . $row['Category'] . "'>" . $row['Category'] . "</option>";
接下來的編輯是填寫表格。 如果查詢不正確,則更改查詢:
// TABLE FILLED FROM DATABASE ACCORDING TO SELECTED OPTION.
$query = "SELECT Category FROM books where category like '" . $_POST["my_option"] . "'";
$result = mysqli_query ($mysqli, $query);
while( $row = mysqli_fetch_array($result) )
echo "<tr>" .
"<td>" . $row['book_name'] . "</td>" .
"<td>" . $row['author'] . "</td>" .
"<td>" . $row['Category'] . "</td>" .
"</tr>";
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