[英]Populating Drop Down Menu from PHP/MYSQL Select Values. How to rearrange output
[英]Select the values in drop down that equals to mysql output
我有一個多下拉框,可以從msyqli輸出生成值,例如阿姆斯特丹,鹿特丹,邁阿密,紐約...
我想選擇等於$ cats中的值的值
到目前為止還可以。
但是問題是下拉列表的值重復。 單擊此處顯示問題如何解決此問題?
$resultxx = mysqli_query($database->connection,"SELECT city FROM postcode
GROUP BY city") or die(mysqli_error());
$cats = explode(",", $ed['ophaal_locaties']);
while($land = mysqli_fetch_array($resultxx)){
$city = $land['city'];
foreach($cats as $cat) {
$cat = trim($cat);
if($cat == $city){
$sl = 'selected';
}else{
$sl = '';
}
echo "<option ".$sl.">".$city."</option>";
}
}
嘗試使用以下SQL查詢-
SELECT DISTINCT(city) FROM postcode
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