[英]Python: How do I randomly select a value from a dictionary key?
我有一本字典:
dict = {
"Apple": ["Green", "Healthy", "Sweet"],
"Banana": ["Yellow", "Squishy", "Bland"],
"Steak": ["Red", "Protein", "Savory"]
}
我想從每個鍵中打印一個隨機值,所以我試着先將它們放入列表中:
import random
food = [dict.value.random.choice()]
但這不起作用(毫不奇怪,它看起來過分和令人困惑)
然后我想print
食物:
print food
並看到:
green
squishy
savory
或隨機選擇的任何值。
正在創建不必要的列表? 我會繼續發布嘗試。
只是為了澄清為什么這不是重復:我不想從字典中隨機抓取一個項目,我想從字典中的每個列表中隨機抓取一個項目。
您可以使用列表推導來循環您的值:
>>> my_dict = {
... "Apple": ["Green", "Healthy", "Sweet"],
... "Banana": ["Yellow", "Squishy", "Bland"],
... "Steak": ["Red", "Protein", "Savory"]
... }
>>> import random
>>> food=[random.choice(i) for i in my_dict.values()]
>>> food
['Savory', 'Green', 'Squishy']
對於你想要的打印,你可以使用join
功能或循環food
並逐個打印元素:
>>> print '\n'.join(food)
Savory
Green
Squishy
>>> for val in food :
... print val
...
Savory
Green
Squishy
您還可以使用for循環:
import random
dict = {
"Apple": ["Green", "Healthy", "Sweet"],
"Banana": ["Yellow", "Squishy", "Bland"],
"Steak": ["Red", "Protein", "Savory"]
}
for key, value in dict.items():
print random.choice(value), key
結果:
Red Steak
Healthy Apple
Bland Banana
使用列表推導,如
import random
choices = [random.choice(v) for k, v in your_dict.items()] # iterate over the dict items
print(choices)
產量
['Protein', 'Green', 'Squishy']
(BTW-將名稱'dict'更改為其他內容)
# for python3
from random import randint
data = {
"Apple": ["Green", "Healthy", "Sweet"],
"Banana": ["Yellow", "Squishy", "Bland"],
"Steak": ["Red", "Protein", "Savory"]
}
for key, value in data.items():
print(key + ":" + value[randint(0,2)])
輸出 (將根據隨機int值改變)
sh-4.2# python3 main.py
Apple:Sweet
Steak:Red
Banana:Squishy
修正案01(@ Selcuk的問題)
for key, value in data.items():
length = len(value)
print(key + ":" + value[randint(0,length-1)])
在徹底瀏覽了文檔並使用上面提供的所有非常有用的答案之后,我發現這是最干凈和最明顯的:
import random
food_char = {
"Apple": ["Green", "Healthy", "Sweet"],
"Banana": ["Yellow", "Squishy", "Bland"],
"Steak": ["Red", "Protein", "Savory"]
}
food=[random.choice(i) for i in food_char.values()]
for item in food:
print item
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