[英]How can I add events to a PictureBox dynamically created by clicking button? (C#)
我通過單擊表單中的按鈕來動態創建一堆PictureBox,但是我不清楚如何向每個事件添加事件。 這是我的主意
private void insertarBloqueToolStripMenuItem_Click(object sender, EventArgs e)
{
pbA = new PictureBox{
Name = "picturebox" + contB,
Image = new Bitmap(bloque),
Size = pbA.Image.Size,
};
pbA.MouseDown += new MouseEventHandler(pbA_MouseDown);
pbA.MouseUp += new MouseEventHandler(pbA_MouseUp);
pbA.MouseMove += new MouseEventHandler(pbA_MouseMove);
pbA.Paint += new PaintEventHandler(pbA_Paint);
pbA.Cursor = Cursors.Hand;
listaBloques.Add(pbA);
panel1.Controls.Add(pbA);
}
那就是我得到的,您能幫我實現這個想法嗎? 以及如何創建一種方法來在列表中移動一個PictureBox? 謝謝
你的想法很好! 但這足以寫(但您的作品也可以):
pbA.Paint += pbA_Paint;// generally: ... += methodName;
並且您必須自行創建事件。 例如:
void pbA_Paint(object sender, System.Windows.Forms.PaintEventArgs e)
{
//do some cool stuff!
}
如果將其繪制在任何 PictureBox上,則將調用此方法。 如果您想知道畫了哪個PictureBox,則只需編寫:
void pbA_Paint(object sender, System.Windows.Forms.PaintEventArgs e)
{
PictureBox picBox_active = sender as PictureBox;
//do some cool stuff!
}
對於只移動一個PictureBox的一種方法,您可以將所需對象作為參數:
void move(PictureBox picBox, int moveX, int moveY)
{
picBox.Location = new Point(moveX, moveY);
}
您可以通過以下方式調用此方法:
PictureBox picBoxTest = new PictureBox();
move(picBoxTest, 5, 5);
並通過一個示例使其更清楚:
void pbA_Paint(object sender, System.Windows.Forms.PaintEventArgs e)
{
PictureBox picBox_active = sender as PictureBox;
move(picBox_active, 5, 5);
}
已繪制的PictureBox將移動到坐標5,5。
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