替換舊的eregi函數PHP

Question

我因使用IN參數來修復此舊的PHP eregi功能時遇到問題。這是來自Matthieu MARY的驗證碼生成class_log.php的腳本

舊代碼：

$sMotif = "--$sIN ([a-zA-Z0-9]{3,4},)*([a-zA-Z0-9]{3,4}){1}";
if ((eregi("$sMotif ",$this->sParam))||(eregi("$sMotif$",$this->sParam))){
    $this->aParam['bExtension'] = TRUE;
    $this->aParam['aExtension'] = $this->_PARAM_get_extension($sIN);
    $this->aParam['inExtension'] = ($sIN=='e');
    $this->aParam['iParameters']++;
}

我嘗試這樣做，但不確定是否正確？

$sMotif = "/--$sIN ([a-zA-Z0-9]{3,4},)*([a-zA-Z0-9]{3,4}){1}/i";
if ((preg_match("$sMotif ",$this->sParam))||(eregi("$sMotif$",$this->sParam))){
    $this->aParam['bExtension'] = TRUE;
    $this->aParam['aExtension'] = $this->_PARAM_get_extension($sIN);
    $this->aParam['inExtension'] = ($sIN=='e');
    $this->aParam['iParameters']++;
}

TNX

Answer 1

這是我完成工作的方式：

$sMotif = "/--$sIN ([a-zA-Z0-9]{3,4},)*([a-zA-Z0-9]{3,4}) ?/";
if ( preg_match($sMotif,$this->sParam)) {