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將JSON發送到服務器不起作用(android)

[英]Send JSON to server not working(android)

對不起我的英語不好。 我有活動注冊,如果用戶單擊“注冊”,我必須將json發送到服務器。 在我擁有舊產品之前,我像這樣發送json:

    ArrayList<NameValuePair> postInform = new ArrayList<NameValuePair>();
                postInform.add(new BasicNameValuePair("php string", "my value"));

try{
operationLink.makeHttpRequest(registrationURL, "POST", postInform);
}catch(Exception e) {}

但是現在我有了新的產品,但它不起作用。 我從服務器收到錯誤消息:

{"message":"Customer data is empty!","status":"error"}

在文檔服務器中,我有示例:

JSON:JSON注冊

{"company_id":"1","phones":["380000505050"],"photo":"/files/clients_photos/tmp/484629825.JPG","name":"sdfsdfdsf","birthdate":"10.02.2014","email":"sdf@sdf.ff","cars":{"1":{"car_brand_id":"9","car_model_id":"856","number":"AE5884AH","photo":"/files/clients_photos/tmp/484629824.JPG"}}}

我的程序創建了asynkTask並發送數據:

private String registrationURL = "http://crm.pavlun.info/api/register"; //working link

//code

    protected Void doInBackground(String... params) {
                JSONParser operationLink = new JSONParser();

                ArrayList<NameValuePair> postInform = new ArrayList<NameValuePair>();
                postInform.add(new BasicNameValuePair("company_id", "1"));
                postInform.add(new BasicNameValuePair("phones", "380950466589"));
                postInform.add(new BasicNameValuePair("name", "Alexy"));
                postInform.add(new BasicNameValuePair("birthdate", "12.03.2014"));
                postInform.add(new BasicNameValuePair("email", "nesalexy@mail.ru"));
                postInform.add(new BasicNameValuePair("photo", "/files/clients_photos/tmp/484629825.JPG"));

                JSONObject registration = null;

                try {
                    Log.e("perform link", postInform.toString());
                    registration = operationLink.makeHttpRequest(registrationURL, "POST", postInform);

                    Log.e("Link", registration.toString());
                }catch(Exception e) {
                    e.printStackTrace();
                }

                return null;
            }

如果我使用像這樣的在線json發送服務器http://gurujsonrpc.appspot.com/ ,則在鏈接中輸入: http://crm.pavlun.info/api/register : http://crm.pavlun.info/api/register在“請求JSON字符串”中,我將其放置

{"company_id":"1","phones":["380034505050"],"photo":"/files/clients_photos/tmp/484629825.JPG","name":"sdfsdfdsf","birthdate":"10.02.2014","email":"sdf@sdf.ff"}

我的網站錯誤發送請求時出錯。 我在我的代碼中做錯了什么???

它是我的JSONParser operationLink = new JSONParser();

public class JSONParser {

    static InputStream is = null;
    static JSONObject jObj = null;
    static String json = "";

    // constructor
    public JSONParser() {

    }

    // function get json from url
    // by making HTTP POST or GET mehtod
    public JSONObject makeHttpRequest(String url, String method,
            List<NameValuePair> params) throws JSONException {

        // Making HTTP request
        try {

            // check for request method
            if(method == "POST"){
                // request method is POST
                // defaultHttpClient
                DefaultHttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost(url);
                httpPost.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));

                HttpResponse httpResponse = httpClient.execute(httpPost);
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();

            }else if(method == "GET"){
                // request method is GET
                DefaultHttpClient httpClient = new DefaultHttpClient();
                String paramString = URLEncodedUtils.format(params, "utf-8");
                url += "?" + paramString;
                HttpGet httpGet = new HttpGet(url);

                HttpResponse httpResponse = httpClient.execute(httpGet);
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();
            }           

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

        // return JSON String 
        return jObj; 
        //return new JSONObject(json.substring(json.indexOf("{"), json.lastIndexOf("}") + 1));

    }
}

我嘗試了您在問題中提供的兩個請求示例,它們都給了我以下答復:

HttpStatus:200 {“ status”:“錯誤”,“消息”:“客戶數據為空!”}

因此,您的問題並不出在您身邊,似乎您缺少一些字段,因此盡管httpStatus不應為200,服務仍會引發錯誤。

我使用chrome中的Advanced Rest Client作為發出其余請求的工具。

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