從兩個不同的表中選擇行，但使用php和MySQL按日期排序

Question

我有兩個桌子。

我正在嘗試生成一份對帳單（如銀行對帳單）以顯示所有費用和所有付款。 費用和付款需要根據statement_date字段以日期順序顯示。

我很確定我需要使用“工會”，但似乎找不到解決方案。

到目前為止，我的努力是；

$statement_sql = "(SELECT * FROM accounts_tenant_charge)
UNION
(SELECT * FROM accounts_tenant_payment)
ORDER BY statement_date";

提前致謝。

Answer 1

謝謝你的幫助。 以下查詢對我有用；

SELECT tenant_charge_date as statement_date, tenant_charge_id as reference, tenant_charge_total_amount as debit, NULL as credit, 'Charge' as type FROM accounts_tenant_charge
UNION ALL
SELECT tenant_payment_date as statement_date, tenant_payment_id as reference, NULL as debit, tenant_payment_amount as credit, 'Payment' as type FROM accounts_tenant_payment
ORDER BY statement_date

Answer 2

您必須進行嵌套查詢。 首先，您根據表進行聯合查詢，並放入內部查詢中。 然后，您進行SELECT查詢並放入外部。 不要忘記為外部查詢提供別名表。

您可以嘗試以下代碼：

SELECT * FROM
(
  (SELECT * FROM accounts_tenant_charge)
   UNION
  (SELECT * FROM accounts_tenant_payment)
) a 
ORDER BY a.statement_date ASC

Answer 3

您的表具有不同的列數，因此不能通過select *立即合並它們。 您必須從兩個表中選擇相等數量的列。 喜歡：

select
  tenant_charge_id as `id`,
  tenant_charge_date as `date`,
  tenant_charge_total_amonunt as `amount`
union
select
  tenant_payment_id,
  tenant_payment_date,
  tenant_payment_amount
order by
  `date` asc