[英]Powershell populate array from list of files
我需要使用基於文件名存儲在目錄中的文件名來填充powershell數組。 對於每組文件(請參閱示例文件夾結構),我都需要一個不同的數組,以用作另一個過程的一部分。
我希望這是自動的並且可以動態創建數組,所以我將擁有包含所有文件名的數組,這些文件名以processor123
開頭,另一個為processorabc
和processorxyz
。 這些數組的名稱可以存儲在另一個名為$arrynames
數組中。 如果引入了新處理器,它必須是動態的,我不想依靠用戶來輸入文件名。
示例文件夾結構;
c:\directory\processor123\processor123.log.20150604
c:\directory\processor123\processor123.log.20150603
c:\directory\processor123\processor123.log.20150602
c:\directory\processor123\processor123.log.20150601
c:\directory\processor123\processor123.log.20150531
c:\directory\processorabc.log.20150604
c:\directory\processorabc.log.20150603
c:\directory\processorabc.log.20150602
c:\directory\processorabc.log.20150601
c:\directory\processorabc.log.20150531
c:\directory\processorxyz.log.20150604
c:\directory\processorxyz.log.20150603
c:\directory\processorxyz.log.20150602
c:\directory\processorxyz.log.20150601
c:\directory\processorxyz.log.20150531
$ ArryNames
processor123
processorabc
processorxyz
$ processor123
c:\directory\processor123\processor123.log.20150604
c:\directory\processor123\processor123.log.20150603
c:\directory\processor123\processor123.log.20150602
c:\directory\processor123\processor123.log.20150601
c:\directory\processor123\processor123.log.20150531
$ processorabc
c:\directory\processorabc.log.20150604
c:\directory\processorabc.log.20150603
c:\directory\processorabc.log.20150602
c:\directory\processorabc.log.20150601
c:\directory\processorabc.log.20150531
因此,您想要對每個字符串執行以下操作:
正如注釋中已經提到的,您可以使用哈希表來保存數組,文件前綴是關鍵:
# Set up a hashtable
$HashTable = @{}
# Pipe your list of file paths to ForEach-Object
Get-Content C:\filenames.txt |ForEach-Object {
# Extract the filename with [System.IO.Path]::GetFileName(), split it by dots and grab only the part before the first dot
$Prefix = [System.IO.Path]::GetFileName($_) -split "\." |Select-Object -First 1
# Use the extracted prefix to place the string in the correct hashtable entry
$HashTable[$Prefix] += $_
}
現在,您可以使用以下命令引用前5個路徑: $HashTable["processor123"]
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