如何等待所有並發任務在同步代碼.NET 4.5中完成？

Question

我有以下ServiceStack Web服務

public class RetreadServices : Service
{
    public IRepository Repository { get; set; }

    //http://stackoverflow.com/questions/18902135/servicestack-no-server-side-async-support

    public async Task<ValidationResponse> Get(RetreadSsnInfoAsync request)
    {
        return await Task.Factory.StartNew(() =>
        {
            Tenant.SetTenant(request.TenantId);
            return new ValidationResponse { Result = Repository.CannotRetreadSsn(request.Ssn) };                    
        });
    }

    public async Task<ValidationResponse> Get(RetreadEmailInfoAsync request)
    {
        return await Task.Factory.StartNew(() =>
        {
            Tenant.SetTenant(request.TenantId);
            return new ValidationResponse { Result = Repository.CannotRetreadEmail(request.Emails) };
        });
    }

    //more methods constructed in the same fashion

}

然后在我的應用程序的單獨類中，我有此方法（基於@StephenCleary的代碼）

private async Task<ValidationResponse[]> DoOperationsConcurrentlyAsync(string tenantId, string[] emails, string ssn)
{
    Task<ValidationResponse>[] tasks =
    {
        ResolveService<RetreadServices>().Get(new RetreadEmailInfoAsync { TenantId = tenantId, Emails = emails }), 
        ResolveService<RetreadServices>().Get(new RetreadSsnInfoAsync { TenantId = tenantId, Ssn = ssn })
    };

    await Task.WhenAll(tasks);

    ValidationResponse[] result = new ValidationResponse[tasks.Length];

    return result;
}

並像這樣被調用

synchronous code...
synchronous code...

var result = DoOperationsConcurrentlyAsync(request.TenantId, request.Emails, request.Ssn);

synchronous code...
synchronous code...

所有這些的目標是等待任務並行執行，並希望減少我的整體時間...但是DoOperationsConcurrentlyAsync需要阻止，我該怎么做？ 然后，作為獎勵，我如何使用async修飾符將返回值從各個任務傳回方法之外？

Answer 1

希望我能正確理解。 但是，您不只是需要添加await關鍵字嗎？

synchronous code...
synchronous code...

var result = await DoOperationsConcurrentlyAsync(request.TenantId, request.Emails, request.Ssn);

synchronous code...
synchronous code...

編輯：獎金問題：再次，我希望我能正確理解你...

但是我將替換為：

await Task.WhenAll(tasks);

ValidationResponse[] result = new ValidationResponse[tasks.Length];

return result;

...簡單地說：

return await Task.WhenAll(tasks);

那應該按照您想要的方式工作。