[英]Using parallel programming in C#
我需要並行執行一個具有不同參數的方法(使用c#)。
我從這里使用說明:
http://www.codeproject.com/Articles/189374/The-Basics-of-Task-Parallelism-via-C
但是我想代替我的Sum(100)
, Sum(200)
, Sum(300)
執行我更復雜的方法Oracle(JIBitArray bits, int rounds, int[] weak_bits_positions)
。
Grain
類的代碼段:
using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace GrainApproximations
{
class Grain
{
JIBitArray NFSR;
JIBitArray LFSR;
JIBitArray key;
const int keysize = 128;
JIBitArray iv;
const int ivsize = 96;
public void Init(JIBitArray key, JIBitArray iv, int rounds)
{
this.key = key;
this.iv = iv;
NFSR = new JIBitArray(keysize);
LFSR = new JIBitArray(keysize);
/* load registers */
//fill NFSR bits with key bits
for (int i = 0; i < keysize; ++i)
{
NFSR.Set(i, this.key.Get(i));
}
for (int i = 0; i < ivsize; ++i)
{
LFSR.Set(i, this.iv.Get(i));
}
//96 < i < 128 bits of LFSR - filling with 1
for (int i = ivsize; i < keysize; i++)
{
LFSR.Set(i, true);
}
/* do initial clockings */
bool outbit;
bool Lbit;
bool Nbit;
for (int i = 0; i < rounds; ++i)
{
outbit = grain_keystream();
Lbit = LFSR.Get(127);
Nbit = NFSR.Get(127);
LFSR.Set(127, outbit ^ Lbit);
NFSR.Set(127, outbit ^ Nbit);
}
}
private bool grain_keystream()
{
bool outbit = NFSR.Get(2) ^ NFSR.Get(15) ^ NFSR.Get(36) ^ NFSR.Get(45) ^ NFSR.Get(64) ^ NFSR.Get(73) ^ NFSR.Get(89) ^ LFSR.Get(93) ^ (NFSR.Get(12) & LFSR.Get(8)) ^ (LFSR.Get(13) & LFSR.Get(20)) ^ (NFSR.Get(95) & LFSR.Get(42)) ^ (LFSR.Get(60) & LFSR.Get(79)) ^ (NFSR.Get(12) & NFSR.Get(95) & LFSR.Get(95));
bool Nbit = LFSR.Get(0) ^ NFSR.Get(0) ^ NFSR.Get(26) ^ NFSR.Get(56) ^ NFSR.Get(91) ^ NFSR.Get(96) ^ (NFSR.Get(3) & NFSR.Get(67)) ^ (NFSR.Get(11) & NFSR.Get(13)) ^ (NFSR.Get(17) & NFSR.Get(18)) ^ (NFSR.Get(27) & NFSR.Get(59)) ^ (NFSR.Get(40) & NFSR.Get(48)) ^ (NFSR.Get(61) & NFSR.Get(65)) ^ (NFSR.Get(68) & NFSR.Get(84));
bool Lbit = LFSR.Get(0) ^ LFSR.Get(7) ^ LFSR.Get(38) ^ LFSR.Get(70) ^ LFSR.Get(81) ^ LFSR.Get(96);
NFSR = NFSR.ShiftLeft(1);
LFSR = LFSR.ShiftLeft(1);
NFSR.Set(keysize - 1, Nbit);
LFSR.Set(keysize - 1, Lbit);
return outbit;
}
public JIBitArray Generate_Gamma_Bits(int length_in_bits)
{
JIBitArray ret = new JIBitArray(length_in_bits);
for (int i = 0; i < length_in_bits; i++)
{
ret.Set(i, grain_keystream());
}
return ret;
}
public JIBitArray Oracle(JIBitArray bits, int rounds, int[] weak_bits_positions)
{
JIBitArray key_bits = bits.SubJIBitArray(0, 128);
JIBitArray iv_bits = bits.SubJIBitArray(128, 96);
JIBitArray[] L_subspace = Build_L_subspace(iv_bits, weak_bits_positions);
for (int i = 0; i < weak_bits_positions.Length; i++)
{
iv_bits.Set(weak_bits_positions[i], false);
}
int count = 0;
bool outbit = false;
JIBitArray gamma = new JIBitArray(1);
for (int i = 0; i < L_subspace.Length; i++)
{
Init(key_bits, iv_bits.Xor(L_subspace[i]), rounds);
outbit = Generate_Gamma_Bits(1).Get(0);
if (outbit)
{
count++;
}
//Console.ReadLine();
}
Console.Write("oracle:");
Console.Write(count % 2);
return count % 2 == 1 ? new JIBitArray(new bool[] { true }) : new JIBitArray(new bool[] { false });
}
public JIBitArray[] Build_L_subspace(JIBitArray iv_bits, int[] weak_bits)
{
JIBitArray[] L_subspace = new JIBitArray[(int)Math.Pow((double)2, (double)weak_bits.Length)];
JIBitArray[] vectors = VectorTable(weak_bits.Length);
for (int i = 0; i < (int)Math.Pow((double)2, (double)weak_bits.Length); i++)
{
L_subspace[i] = new JIBitArray(iv_bits.Count);
for (int j = 0; j < weak_bits.Length; j++)
{
L_subspace[i].Set(weak_bits[j], vectors[i].Get(j));
}
}
return L_subspace;
}
//build table of all vectors of k variables
public static JIBitArray[] VectorTable(int k)
{
int rows = (int)Math.Pow((double)2, (double)k);
bool[] tmp = new bool[k];
JIBitArray[] result = new JIBitArray[rows];
string x = string.Empty;
char[] characters = new char[0];
bool[] vector = new bool[0];
for (int i = 0; i < rows; i++)
{
x = Convert.ToString(i, 2);
x = x.PadLeft(k, '0');
characters = x.ToCharArray();
vector = new bool[characters.Length];
for (int j = 0; j < characters.Length; j++)
{
if (characters[j] == '1')
{
vector[j] = true;
}
else
{
vector[j] = false;
}
}
result[i] = new JIBitArray(vector);
}
return result;
}
}
}
JIBitArray
它是標准的.NET集合BitArray
的修改版本:
http://www.codeproject.com/Articles/14430/My-BitArray-Class
在Main
方法中,我嘗試執行:
Grain grain = new Grain();
Task<bool[]> parent = new Task<bool[]>(() =>
{
var results = new bool[5]; // Create an array for the results
// This tasks creates and starts 3 child tasks
for (int i = 0; i < results.Length; i++)
{
new Task(() => results[i] = grain.Oracle(bits[i], rounds, weak_bits).Get(0), TaskCreationOptions.AttachedToParent).Start();
}
// Returns a reference to the array
// (even though the elements may not be initialized yet)
return results;
});
// When the parent and its children have
// run to completion, display the results
var cwt = parent.ContinueWith(parentTask =>
Array.ForEach(parentTask.Result, Console.WriteLine));
// Start the parent Task so it can start its children
parent.Start();
cwt.Wait(); // For testing purposes
其中bits
-這是5個不同JIBitArray
二進制向量的數組,長度為128 + 96 = 224位。
但是我在計算時得到了System.AggregateException
和System.ArgumentOutOfRangeException
。
我使用TPL是因為我需要使用不同的輸入參數執行2 ^ 20個任務( bits
具有2 ^ 20個元素)
有人可以解釋什么地方不對嗎?
一個問題是您沒有捕獲循環變量i。 到內部任務執行時,我已經是5。
但是您似乎也沒有等待內部任務的結果。 為什么不將內部任務Task<bool>
以便獲得(並等待)其結果?
同樣,按照您的父任務的說法,這毫無意義,如果您要做的就是啟動其他任務(只要其中沒有長時間運行的計算),則只需使用一種方法即可。 如果您希望它有用,它將等待子任務完成,然后返回合並的結果。
使用Parallel.ForEach
將使此代碼更簡單,並且更有可能實現您要執行的操作。
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