[英]MySQL: how to group the sum of two columns that return more than one value?
我有個問題。
我有這兩個表需要計算每個表的列的總和。 表與partnumber有關系。
問題是每個表返回多個值。
物料清單是bom
id finishgood partnumber qty
1 F1920-10 3122E 3
2 F1920-10 AE3030 4
3 F1920-10 3122E 2
4 F1920-10 5538WM 1
5 F1920-10 9803K 2
6 F1920-10 9722F 1
7 F1920-10 9722F 2
8 F1920-10 1001A 1
9 E2020-10 AB123 2
庫存物料AS項目
id partnumber LOT onHand
1 3122E M01 105
2 3122E M10 23
3 AE3030 M02 30
4 5538WM M02 15
5 9803K M10 133
6 9722F M15 45
7 9722F M30 55
8 9722F M01 150
9 1001A M10 NULL
這是我的查詢
SELECT bom.finishgood, bom.partnumber, SUM(bom.qty), SUM(item.onHand)
FROM bom
left outer join item ON item.partnumber = bom.partnumber
WHERE bom.partnubmer = 'F1920-10'
GROUP BY bom.partnumber
這是我的結果
partnumber sum(qty) ERROR sum(onHand)
3122E 10 5*2 128
AE3030 3 ok 30
5538WM 1 ok 15
9803K 2 ok 133
9722F 9 3*3 250
添加更多值時會添加到另一個表的行中。
這是理想的結果
partnumber sum(bom.qty) sum(items.onHand)
3122E 5 128
AE3030 3 30
5538WM 1 15
9803K 2 133
9722F 3 250
他們有什么想法嗎? 我很沮喪感謝您的回答。
SELECT
DerivedTotalByPart.PartNumber AS [partnumber],
[BOM Total] AS [sum(bom.qty)],
DerivedTotalOnHand.TotalOnHand AS [sum(items.onHand)]
FROM
(
SELECT
bom.partNumber AS [PartNumber],
SUM(bom.qty) AS [BOM Total]
FROM
bom
WHERE
bom.finishgood = 'F1920-10'
GROUP BY
bom.partNumber
) DerivedTotalByPart
LEFT OUTER JOIN
(
SELECT
partnumber,
ISNULL(SUM(onhand), 0) AS [TotalOnHand]
FROM
item
GROUP BY
partnumber
) DerivedTotalOnHand ON DerivedTotalByPart.PartNumber = DerivedTotalOnHand.PartNumber
可以使用UNION
,可以使用子選擇...這是我最喜歡的MySQL資源之一: http : //www.artfulsoftware.com/infotree/queries.php
一個選擇是......
SELECT s1 + s2 FROM (
SELECT
(SELECT SUM(item.onHand) FROM item WHERE bom.partnubmer = 'F1920-10') s1,
(SELECT SUM(bom.qty) FROM bom WHERE bom.partnubmer = 'F1920-10') s2
) foo;
@Christian,SQL中的聚合函數返回的值只有一列和一行。 它們包括SUM(),AVG(),MIN(),MAX()等......因此,使用聚合函數和非聚合函數會出現錯誤。 嘗試計算單獨sql中項目的總和,並查看返回的結果。
例
SELECT SUM(bom.qty), SUM(item.onHand) FROM bom left outer join item ON item.partnumber = bom.partnumber WHERE bom.partnubmer = 'F1920-10' GROUP BY bom.partnumber
您可以使用此查詢:
SELECT
bom2.partnumber,
bom2.qtySum,
item2.onHandSum
FROM
(
SELECT
partnumber,
sum(qty) qtySum
FROM
bon
GROUP BY
partnumber
) bom2
INNER JOIN (
SELECT
partnumber,
sum(onHand) onHandSum
FROM
item
GROUP BY
partnumber
) item2 ON item2.partnumber = bom2.partnumber
WHERE bom.partnubmer = 'F1920-10'
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