MySQL: how to group the sum of two columns that return more than one value?

Question

I have a problem.

I have these two tables need to calculate the sum of a column of each table. tables have a relationship with partnumber.

the problem is that each table returns more than one value.

Bill of material AS bom

id  finishgood  partnumber  qty
1   F1920-10    3122E       3
2   F1920-10    AE3030      4
3   F1920-10    3122E       2
4   F1920-10    5538WM      1
5   F1920-10    9803K       2
6   F1920-10    9722F       1
7   F1920-10    9722F       2
8   F1920-10    1001A       1
9   E2020-10    AB123       2

Inventory Items AS item

id  partnumber  LOT     onHand
1   3122E       M01     105
2   3122E       M10     23
3   AE3030      M02     30
4   5538WM      M02     15
5   9803K       M10     133
6   9722F       M15     45
7   9722F       M30     55
8   9722F       M01     150
9   1001A       M10     NULL

This is my query

SELECT bom.finishgood, bom.partnumber, SUM(bom.qty), SUM(item.onHand)
FROM bom
left outer join item ON item.partnumber = bom.partnumber
WHERE bom.partnubmer = 'F1920-10'
GROUP BY bom.partnumber

This is my result

partnumber  sum(qty)    ERROR   sum(onHand)
3122E       10          5*2     128
AE3030      3           ok      30
5538WM      1           ok      15
9803K       2           ok      133
9722F       9           3*3     250

on adding more values are added to the rows in the other table.

This is the ideal result

partnumber  sum(bom.qty)    sum(items.onHand)
3122E       5           128
AE3030      3           30
5538WM      1           15
9803K       2           133
9722F       3           250

They have any idea? I'm frustrated Thanks for your answer.

Answer 1

SELECT
    DerivedTotalByPart.PartNumber AS [partnumber],
    [BOM Total] AS [sum(bom.qty)],
    DerivedTotalOnHand.TotalOnHand AS [sum(items.onHand)]
FROM
    (   
    SELECT 
        bom.partNumber AS [PartNumber],
        SUM(bom.qty) AS [BOM Total] 
    FROM
         bom 
    WHERE
        bom.finishgood = 'F1920-10'
    GROUP BY
        bom.partNumber
    ) DerivedTotalByPart
    LEFT OUTER JOIN
    (
    SELECT
        partnumber,
        ISNULL(SUM(onhand), 0) AS [TotalOnHand]
    FROM
        item
    GROUP BY
        partnumber
    ) DerivedTotalOnHand ON DerivedTotalByPart.PartNumber = DerivedTotalOnHand.PartNumber

Answer 2

Could use a UNION , could use sub selects... Here is one of my favorite MySQL resources: http://www.artfulsoftware.com/infotree/queries.php

one option is...

SELECT s1 + s2 FROM (
    SELECT 
    (SELECT SUM(item.onHand) FROM item WHERE bom.partnubmer = 'F1920-10') s1,
    (SELECT SUM(bom.qty) FROM bom WHERE bom.partnubmer = 'F1920-10') s2
) foo;

Answer 3

@Christian, Aggregate functions in SQL returns a value of only one column and one row. They include SUM(), AVG(), MIN(), MAX(), etc... So using aggregate functions together with non-aggregate functions is prior to errors. Try calculating the sum of the items in a separate sql and see the results returned.

Example

SELECT SUM(bom.qty), SUM(item.onHand) FROM bom left outer join item ON item.partnumber = bom.partnumber WHERE bom.partnubmer = 'F1920-10' GROUP BY bom.partnumber

Answer 4

You can use this query:

SELECT 
    bom2.partnumber,
    bom2.qtySum,
    item2.onHandSum
FROM
    (
        SELECT 
            partnumber,
            sum(qty) qtySum
        FROM
            bon
        GROUP BY 
            partnumber
        ) bom2 
    INNER JOIN (
        SELECT 
            partnumber,
            sum(onHand) onHandSum 
        FROM
            item
        GROUP BY 
            partnumber
        ) item2 ON item2.partnumber = bom2.partnumber
WHERE bom.partnubmer = 'F1920-10'