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[英]How can I initialize a C# List in the same line I declare it. (IEnumerable string Collection Example)
[英]How can I Create a Collection of Lists in C# and initialize data to it
我想為Windows商店應用程序上的媒體創建示例數據,我創建了如下所示的DigitalMedia類
public class DigitalMedia
{
public string Title { get; set; }
public string Author { get; set; }
public string Subject { get; set; }
public string Format { get; set; }
public double Duration { get; set; }
public string Description { get; set; }
public ImageSource TitleImage { get; set; }
public ImageSource Thumbnail { get; set; }
public Uri PurchaseLink { get; set; }
}
我還創建了另一個名為GroupedMedia的類來表示DigitalMedia類的組。 此代碼如下
public class GroupedMedia : INotifyPropertyChanged
{
public string GroupTitle { get; set; }
public string Description { get; set; }
public ImageSource GroupImage { get; set; }
private ObservableCollection<DigitalMedia> _mediaList = null;
public ObservableCollection<DigitalMedia> MediaList
{
get
{
if (_mediaList == null)
_mediaList = new ObservableCollection<DigitalMedia>();
return _mediaList;
}
set
{
_mediaList = value;
RaisePropertyChanged("MediaList");
}
}
public event PropertyChangedEventHandler PropertyChanged;
private void RaisePropertyChanged(string property)
{
if (PropertyChanged != null)
PropertyChanged(this, new PropertyChangedEventArgs(property));
}
1-如果只是出於測試目的,則可以簡單地將對象的初始化添加到MainWindow.xaml.cs的InitializeComponent()下。
3-像這樣在主窗口中放置一個DataGrid:
<Window x:Class="WpfApplication7.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid>
<DataGrid Name="dgTest"></DataGrid>
</Grid>
</Window>
然后將其ItemsSource設置為您的數據。
public MainWindow()
{
InitializeComponent();
//Initialize your data here
GroupedMedia gm = new GroupedMedia();
//Initialize your data here
this.dgTest.ItemsSource = gm.MediaList;
}
試試這個
static void Main(string[] args)
{
GroupedMedia groupedMedia = new GroupedMedia();
List<DigitalMedia> digitalMedias = new List<DigitalMedia>();
for(int i = 0; i < 5; i++)
{
DigitalMedia digitalMedia = new DigitalMedia();
digitalMedias.Add(digitalMedia);
digitalMedia.Author = "John";
}
groupedMedia.MediaList = digitalMedias;
}
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