僅顯示上傳的圖像

Question

控制器：

[HttpPost]
public ActionResult UploadImage(List<HttpPostedFileBase> files)
{
    EntityDBContext db = new EntityDBContext();
    var imagesShown = db.Images.ToList();

    foreach (var file in files)
    {
        if (file != null)
        {
            string imageName = Path.GetFileName(file.FileName);
            string physicalPath = Server.MapPath("~/Images/" + imageName);
            byte[] pictureAsBytes = new byte[file.ContentLength];

            using (BinaryReader br = new BinaryReader(file.InputStream))
            {
                pictureAsBytes = br.ReadBytes(file.ContentLength);
            }

            //Save to folder
            file.SaveAs(physicalPath);

            //Save new record in database
            Image img = new Image();

            img.ImageName = imageName;
            img.ImageBytes = pictureAsBytes;

            db.Images.Add(img);
            db.SaveChanges();

            //Only show images that user uploaded, not entire database
            imagesShown = imagesShown.Where(x => x.ImageName == imageName).ToList();
        }
        else
        {
            return View("Index");
        }
    }

    return View("ShowImage", imagesShown);
}

視圖：

@model IEnumerable<Vidafo.Models.Image>

@foreach(var image in Model)
{
    <img src="data:image; base64, @System.Convert.ToBase64String(image.ImageBytes)" />
}

我試圖僅顯示用戶使用IQueryable行上傳的圖像，但這不是很好，因為如果名稱已經在數據庫中，它將發布所有圖像。

我只希望顯示他們剛剛上傳的用戶照片。 不是整個數據庫，我該怎么做？ 我想我必須以某種方式使用“文件”，但不確定如何使用。

Answer 1

以下代碼段僅導致一次保存，並且僅返回新上傳的圖像（我尚未測試您的文件上傳代碼，因此假設它運行正常）：

[HttpPost]
public ActionResult UploadImage(List<HttpPostedFileBase> files)
{
    EntityDBContext db = new EntityDBContext();
    List<Image> uploadedImages = new List<Image>();

    foreach (var file in files)
    {
        if (file != null)
        {
            string imageName = Path.GetFileName(file.FileName);
            string physicalPath = Server.MapPath("~/Images/" + imageName);
            byte[] pictureAsBytes = new byte[file.ContentLength];

            using (BinaryReader br = new BinaryReader(file.InputStream))
            {
                pictureAsBytes = br.ReadBytes(file.ContentLength);
            }

            //Save to folder
            file.SaveAs(physicalPath);

            //Save new record in database
            Image img = new Image
                {
                    ImageName = imageName;
                    ImageBytes = pictureAsBytes;
                };

            uploadedImages.Add(img);
        }
    }
    db.Images.AddRange(uploadedImages);
    db.SaveChanges();
    return View("ShowImage", uploadedImages);
}