[英]Segmentation fault around MD5 code
當我運行此md5代碼時,它在運行時最多需要輸入64個字符的長度。 每當我輸入的字符數超過64個時,就會顯示
Inconsistency detected by ld.so: dl-fini.c: 205: _dl_fini: Assertion ns != 0 || i == nloaded failed!
我需要哈希將近10kb的輸入(僅字符串)。 我需要更改頭文件中的任何內容嗎? 誰能告訴我解決方案?
md5.h
#ifndef HEADER_MD5_H
#define HEADER_MD5_H
#include <openssl/e_os2.h>
#include <stddef.h>
#ifdef __cplusplus
extern "C" {
#endif
#ifdef OPENSSL_NO_MD5
#error MD5 is disabled.
#endif
/*
* !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
* ! MD5_LONG has to be at least 32 bits wide. If it's wider, then !
* ! MD5_LONG_LOG2 has to be defined along. !
* !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
*/
#if defined(__LP64__)
#define MD5_LONG unsigned long
#elif defined(OPENSSL_SYS_CRAY) || defined(__ILP64__)
#define MD5_LONG unsigned long
#define MD5_LONG_LOG2 3
/*
* _CRAY note. I could declare short, but I have no idea what impact
* does it have on performance on none-T3E machines. I could declare
* int, but at least on C90 sizeof(int) can be chosen at compile time.
* So I've chosen long...
* <appro@fy.chalmers.se>
*/
#else
#define MD5_LONG unsigned long
#endif
#define MD5_CBLOCK 64
#define MD5_LBLOCK (MD5_CBLOCK/2)
#define MD5_DIGEST_LENGTH 16
typedef struct MD5state_st
{
MD5_LONG A,B,C,D;
MD5_LONG Nl,Nh;
MD5_LONG data[MD5_LBLOCK];
unsigned int num;
} MD5_CTX;
#ifdef OPENSSL_FIPS
int private_MD5_Init(MD5_CTX *c);
#endif
int MD5_Init(MD5_CTX *c);
int MD5_Update(MD5_CTX *c, const void *data, size_t len);
int MD5_Final(unsigned char *md, MD5_CTX *c);
unsigned char *MD5(const unsigned char *d, size_t n, unsigned char *md);
void MD5_Transform(MD5_CTX *c, const unsigned char *b);
#ifdef __cplusplus
}
#endif
#endif
md5.c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "md5.h"
char *pt(char *, int );
int main(int argc, char **argv)
{
char *in;
char *out;
printf("ENter the string\n");
scanf("%[^\n]s",in);
size_t len; //unsigned long len; size_t len;
len = printf("len is %d\n",strlen(in));
out = pt(in, len);
printf("MD5 is\t: %s\n", out);
free(out);
//return 0;
}
char *pt(char *str, int length)
{
int n;
MD5_CTX c;
unsigned char digest[16];
char *output = (char*)malloc(33);
MD5_Init(&c);
MD5_Update(&c, str, length);
MD5_Final(digest, &c);
for (n = 0; n < 16; ++n)
{
sprintf(&output[n*2], "%02x", (unsigned int)digest[n]);
}
return output;
}
問題1
對於此語句:
scanf("%[^\n]s",in);
當我使用-Wall
標志進行編譯時,得到警告:
warning: 'in' is used uninitialized in this function [-Wuninitialized] scanf("%[^\\n]s",in); ^
如您所見, in
沒有指向內存中的任何位置,因此您首先需要使用數組或malloc()
分配一些內存:
char in[500]; //or a higher value
char *out;
printf("Enter the string\n");
scanf("%499[^\n]s", in);
printf("\nin = .%s.\n", in);
要么
char *in;
char *out;
in = malloc(500); //or a higher value
printf("Enter the string\n");
scanf("%499[^\n]s", in);
printf("\nin = .%s.\n", in);
可能的問題2
您正在將printf()
的返回值分配給變量len
。
len = printf("len is %d\n",strlen(in));
返回值printf
:
成功返回后,它將返回打印的字符數(不包括用於結束輸出到字符串的空字節)。
假設希望變量len
為包含字符串的長度in
和打印的字符不是數字printf("len is %d\\n",strlen(in))
,則可能要分配從返回strlen()
第一:
len = strlen(in);
printf("len is %d\n", len);
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