如何對具有多個關鍵屬性的字典列表進行排序-Python

Question

我正在嘗試基於兩個關鍵參數-“ id”和“ type”對列表字典進行排序。 假設您有一個類似以下的列表

dict_list = [
    { "id" : 1, "type" : "snippet", "attribute" :'test'},
    { "id" : 2, "type" : "snippet", "attribute" :'hello'},
    { "id" : 1, "type" : "code", "attribute" : 'wow'},
    { "id" : 2, "type" : "snippet", "attribute" :'hello'},
 ]

最終結果應該是這樣的。

dict_list = [
    { "id" : 1, "type" : "snippet",　"attribute" : 'test'　},
    {　"id" : 2,　"type" : "snippet",　"attribute" :　'hello'　},
    {　"id" : 1,　"type" : "code",　"attribute" : 'wow'　},
]

我嘗試了這種方法，但它僅基於“ key”屬性僅生成一個唯一列表。

unique_list = {v['id'] and v['type']:v  for v in dict_list}.values()

如何基於兩個關鍵參數生成唯一列表？

Answer 1

seen_items = set()
filtered_dictlist = (x for x in dict_list 
                     if (x["id"], x["type"]) not in seen_items 
                     and not seen_items.add((x["id"], x["type"])))
sorted_list = sorted(filtered_dictlist,
                     key=lambda x: (x["type"], x["id"]),
                     reverse=True)

我認為應該先過濾，然后按需要對其進行排序...

您可以使用itemgetter使它更優雅

from operator import itemgetter
my_getter = itemgetter("type", "id")
seen_items = set()
filtered_values = [x for x in dict_list 
                   if my_getter(x) not in seen_items 
                   and not seen_items.add(my_getter(x))]
sorted_list = sorted(filtered_dictlist, key=my_getter, reverse=True)