帶有用戶輸入的二次公式（Java）

Question

我是編碼方面的新手，我不太確定如何100％寫出這個問題。 我試圖弄清楚為什么我的程序只存儲值“ a”的第一個輸入，即使該數字為負數也是如此。

例如：a = -1（值必須大於0。再次輸入值'a'：） a = 1 b = 3 c = -4

因此，在程序編譯時，僅存儲了“ a”（-1）的第一個值，而不存儲第二個值（1），並且在遇到第二個if代碼塊時終止了程序。 我完全不知道如何解決這個問題：/

這是我的代碼：

package quadratic;

import java.util.*;

//Program that does quadratic equations
public class Quadratic{
    public static void main(String[] args){

        boolean run = true;
        while(run){ //if program completes true, will start program again
            Scanner sc = new Scanner(System.in); // set scanner to allow user input

            System.out.println("Please enter value for 'a':");
            double a = (sc.nextDouble()); //looking for user input
            if (a <= 0){
                System.out.print("Value must be greater than 0. Enter value 'a' again:\n");
                sc.nextDouble(); //prompt user again if value less than or equal to 0
            }
            System.out.println("Please enter value for 'b':");
            double b = (sc.nextDouble());
            System.out.println("Please enter value for 'c':");
            double c = (sc.nextDouble());
            System.out.printf("Values entered: a:%s b:%s c:%s \n",a,b,c);

            if (Math.pow(b,2)- (4 * a * c) <= 0){
                System.out.println("Impossible. Program Terminating");
                System.exit(0); //Terminate program
            }

            double qf1 = (-b + Math.sqrt(Math.pow(b, 2) - (4 * a * c))) / (2 * a);
            double qf2 = (-b - Math.sqrt(Math.pow(b, 2) -(4 * a * c)))/ (2 * a);
            // qf stands for Quadratic Formula
            System.out.printf("Anwser One: %s \n", qf1); //%s whatever qf1 returned
            System.out.printf("Anwser Two: %s \n", qf2); //%s whatever qf2 returned
        }
    }
}

Answer 1

你只是打電話

sc.nextDouble(); //prompt user again if value less than or equal to 0

不

a = sc.nextDouble(); //prompt user again if value less than or equal to 0

所以，您只是丟掉第二個數字

此外，您可以第二次輸入負數，因為您無需檢查該數字是否小於零（提示：可能是循環，直到輸入了有效的a值？）

Answer 2

 if (a <= 0){
    System.out.print("Value must be greater than 0. Enter value 'a' again:\n");
    sc.nextDouble(); //prompt user again if value less than or equal to 0
    }

將上面的代碼替換為：

 if (a <= 0){
    System.out.print("Value must be greater than 0. Enter value 'a' again:\n");
    a = sc.nextDouble(); //prompt user again if value less than or equal to 0
    }

另外 ，您應該使用循環而不是if語句，例如：

 while (a <= 0){
    System.out.print("Value must be greater than 0. Enter value 'a' again:\n");
    a = sc.nextDouble(); //prompt user again if value less than or equal to 0
    }