隨機化Python OrderedDict的順序

Question

samplesDict是OrderedDict對象的samplesDict ； 來自Python集合 。 對於每個OrderedDict，我想創建一個副本，其中訂單是隨機的。

import collections
import copy
import random
...
randomizedSamplesDict = copy.deepcopy(samplesDict)
for k, i in samplesDict.iteritems():
  random.shuffle(i)

但是我一直收到random.shuffle(i) KeyError: 56在random.shuffle(i)行上是KeyError: 56 ； 誤差整數（例如56 ）每次都不同。

為了說明，OrderedDicts之一可能是

OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])

我希望副本成為

OrderedDict([
  ('Finally the third key', ['bar', 'foo']),
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz'])])

Answer 1

要隨機化一個OrderedDict，您可以執行以下操作：

od = collections.OrderedDict([('This is the first key', ['foo', 'baz']), ('And the second key', ['buz', 'baz']),  ('Finally the third key', ['bar', 'foo'])])
items = od.items()
random.shuffle(items)
odrnd = collections.OrderedDict(items)
ornd
OrderedDict([('Finally the third key', ['bar', 'foo']), ('This is the first key', ['foo', 'baz']), ('And the second key', ['buz', 'baz'])])

Answer 2

我不確定您要在這里做什么？ 但這是獲得最終結果的一種方法：

ordered_dicts = samplesDict.values()

現在，如果要隨機獲取有序的字典，請執行以下操作：

random.choice(ordered_dict)

如果要隨機從其中一個命令獲取值：

the_dict_you_want = 1
random.choice([value for value in ordered_dicts[the_dict_you_want].values()])

如果您只想從排序的字典中隨機獲得項目的順序，請將其轉換為普通字典； 然后隨機播放鍵。

Answer 3

import collections
import copy
import random

samplesDict = collections.OrderedDict()
samplesDict[1] = 10
samplesDict[2] = 20
samplesDict[3] = 30
print samplesDict

keys = samplesDict.keys()
random.shuffle(keys)
print keys

randomizedSamplesDict = collections.OrderedDict()
for k in keys :
    randomizedSamplesDict[k] = samplesDict[k]
print randomizedSamplesDict

輸出：

OrderedDict([(1, 10), (2, 20), (3, 30)])
[2, 1, 3]
OrderedDict([(2, 20), (1, 10), (3, 30)])

如您所見，第二個dict（通過鍵）被拖曳了。

使用您的數據，我得到輸出：

...
samplesDict = collections.OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])
...

OrderedDict([('This is the first key', ['foo', 'baz']), 
('And the second key', ['buz', 'baz']), 
('Finally the third key', ['bar', 'foo'])])

['And the second key', 'Finally the third key', 'This is the first key']

OrderedDict([('And the second key', ['buz', 'baz']), 
('Finally the third key', ['bar', 'foo']), 
('This is the first key', ['foo', 'baz'])])

Answer 4

您洗錯了項目，應該遍歷randomizedSamplesDict ：

randomizedSamplesDict = copy.deepcopy(samplesDict)
for k, i in randomizedSamplesDict.items():
  random.shuffle(i)
print(randomizedSamplesDict)

您已經對samplesDict進行了samplesDict因此，如果您要在randomizedSamplesDict中samplesDict順序，則需要迭代該字典而不是原始字典。

如果您實際上想要一個隨機字典中帶有來自samplesDict的鍵和值的新字典，則在改組后使用原始字典中的項來創建新的OrderedDict：

import collections
import copy
import random
samplesDict = collections.OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])

items = list(samplesDict.items())
random.shuffle(items)
randomizedSamplesDict = collections.OrderedDict(copy.deepcopy(items))

Answer 5

import random
from collections import defaultdict, OrderedDict

randomizedSamplesDict = defaultdict(list)
for category, samples in samplesDict.iteritems():
  # samples is an OrderedDict object
  keys = samples.keys()
  random.shuffle(keys)
  tempOrderedDict = OrderedDict()
  for k in keys:
    tempOrderedDict[k] = samples[k]
  randomizedSamplesDict[category] = tempOrderedDict

return randomizedSamplesDict

Answer 6

在Python 3.6+中，字典是有序的，因此以前起作用的解決方案可能會產生類似TypeError: 'odict_items' object does not support indexing錯誤TypeError: 'odict_items' object does not support indexing 。

相反，請嘗試：

items = list(my_dict.items())
random.shuffle(items)
my_dict = OrderedDict(items)