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[英]Disable weekdays and holidays in jQuery datepicker issue in WooCommerce
[英]How to disable weekdays and custom days in jquery datepicker?
這是我下面的代碼,我需要禁用工作日,並且在給定的日子里我該怎么做? 有人能幫我嗎 ?
jQuery 小提琴
$(document).ready(function(){
var Desingndate = $('#DesignIdUnavialble').html();
var splitdate = Desingndate.split(',');
// console.log(splitdate.length);
var arrDisabledDates = {};
for (var i = 0; i < splitdate.length; i++) {
//console.log(splitdate[i]);
arrDisabledDates[new Date(splitdate[i])] = new Date(splitdate[i]);
}
$("#iDate").datepicker({
dateFormat: 'dd-mm-yy',
beforeShowDay: function (dt) {
var bDisable = arrDisabledDates[dt];
if (bDisable) return [false, '', ''];
else return [true, '', ''];
}
});
});
我修改了您的else語句以禁用所有工作日:
var bDisable = arrDisabledDates[dt];
if (bDisable) return [false, '', ''];
else {
return [dt.getDay() == 6 || dt.getDay() == 0,""];
}
這可能對您有幫助
function deadlinedates(date) {
dmy = date.getDate() + "-" + (date.getMonth()+1) + "-" + date.getFullYear();
var day = date.getDay();
var Desingndate = $('#DesignIdUnavialble').html();
var splitdate = Desingndate.split(',');
var arrDisabledDates = {};
for (var i = 0; i < splitdate.length; i++) {
arrDisabledDates[new Date(splitdate[i])] = new Date(splitdate[i]);
}
var bDisable = arrDisabledDates[date];
if (bDisable) return [false, '', ''];
else return [(day != 0 && day != 6)];
}
$(document).ready(function(){
$("#iDate").datepicker({
dateFormat: 'dd-mm-yy',
beforeShowDay: deadlinedates
});
});
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