安裝pyobjc時出錯：Anaconda2.1 python3.4或2.7，OSX 10.9

Question

sudo pip install pyobjc返回：

      File "/Users/USER/anaconda/lib/python2.7/subprocess.py", line 573, in check_output
        raise CalledProcessError(retcode, cmd, output=output)
    subprocess.CalledProcessError: Command '['/usr/bin/xcodebuild', '-version', '-sdk', 'macosx', 'Path']' returned non-zero exit status 1

    ----------------------------------------
Command "python setup.py egg_info" failed with error code 1 in /private/var/folders/48/0c48tlds0knggddqs9lwf5900000gn/T/pip-build-RZEwHr/pyobjc-core

而兩者

easy_install -U pyobjc

和

python install setup.py install

返回

xcode-select: error: tool 'xcodebuild' requires Xcode, but active developer directory '/Library/Developer/CommandLineTools' is a command line tools instance
Traceback (most recent call last):
  File "setup.py", line 185, in <module>
    keywords=['Objective-C', 'bridge', 'Cocoa'],

...更多行輸出...文件“ /Users/USER/anaconda/lib/python2.7/pickle.py”，行1382，在加載中返回Unpickler（file）.load（）文件“ / Users /負載分配密鑰文件“ /Users/USER/anaconda/lib/python2.7/pickle.py”中的USER / anaconda / lib / python2.7 / pickle.py”行858行，在load_reduce值= func（ * args）TypeError： init （）至少接受3個參數（給定1個）

至少其他一些人也遇到了類似的問題： 在OSX 10.10.2的Anaconda python上安裝pyobjc的錯誤

有人解決了嗎？

Answer 1

OSX的最新版本附帶了預編譯的PyObjc，如果您能夠使用Mac版本的Python，則應該能夠將其導入：python

Python 2.7.6 (default, Sep  9 2014, 15:04:36) 
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.39)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import objc
>>> objc.__path__
['/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC/objc']