使用正則表達式從文本文件中提取字符串

Question

從本質上講，我有一個txt文檔，

The sound of a horse at a gallop came fast and furiously up the hill.
"So-ho!" the guard sang out, as loud as he could roar.
"Yo there! Stand! I shall fire!"
The pace was suddenly checked, and, with much splashing and floundering, a man's voice called from the mist, "Is that the Dover mail?"
"Never you mind what it is!" the guard retorted. "What are you?"
"_Is_ that the Dover mail?"
"Why do you want to know?"
"I want a passenger, if it is."
"What passenger?"
"Mr. Jarvis Lorry."
Our booked passenger showed in a moment that it was his name.
The guard, the coachman, and the two other passengers eyed him distrustfully.

使用正則表達式，我需要在雙引號中打印所有內容，我不想要完整的代碼，我只需要知道我應該如何去做，哪個正則表達式將是最有用的。 提示和指示，請！

Answer 1

r'(".*?")'將匹配雙引號中的每個字符串。 括號表示捕獲的組. 匹配每個字符（換行符除外）， *表示重復，而? 使它變得非貪婪（在下一個雙引號之前停止匹配）。 如果需要，請在re.DOTALL選項中添加make . 還匹配換行符。

Answer 2

這應該做到（下面有解釋）：

from __future__ import print_function

import re

txt = """The sound of a horse at a gallop came fast and furiously up the hill.
"So-ho!" the guard sang out, as loud as he could roar.
"Yo there! Stand! I shall fire!"
The pace was suddenly checked, and, with much splashing and floundering,
a man's voice called from the mist, "Is that the Dover mail?"
"Never you mind what it is!" the guard retorted. "What are you?"
"_Is_ that the Dover mail?"
"Why do you want to know?"
"I want a passenger, if it is."
"What passenger?"
"Mr. Jarvis Lorry."
Our booked passenger showed in a moment that it was his name.
The guard, the coachman, and the two other passengers eyed him distrustfully.
"""

strings = re.findall(r'"(.*?)"', txt)

for s in strings:
    print(s)

結果：

So-ho!
Yo there! Stand! I shall fire!
Is that the Dover mail?
Never you mind what it is!
What are you?
_Is_ that the Dover mail?
Why do you want to know?
I want a passenger, if it is.
What passenger?
Mr. Jarvis Lorry.

r'"(.*?)"'將匹配雙引號中的每個字符串。 括號表示捕獲組，因此您只會得到不帶雙引號的文本。 的. 匹配每個字符（換行符除外）， *表示“最后一件事零個或多個”，最后一個是. 。 ? *使得* “非貪婪”，這意味着它匹配的越少越好。 如果您不使用? ，您只會得到一個結果； 一個字符串，其中包含第一個和最后一個雙引號之間的所有內容。

您可以包括re.DOTALL標志，以便. 如果要提取與行交叉的字符串，還將匹配換行符。 如果要這樣做，請使用re.findall(r'"(.*?)"', txt, re.DOTALL) 。 換行符將包含在字符串中，因此您必須進行檢查。

解釋不可避免地類似於/基於@ TigerhawkT3的答案。 也投票給那個答案！