使用正则表达式从文本文件中提取字符串

Question

从本质上讲，我有一个txt文档，

The sound of a horse at a gallop came fast and furiously up the hill.
"So-ho!" the guard sang out, as loud as he could roar.
"Yo there! Stand! I shall fire!"
The pace was suddenly checked, and, with much splashing and floundering, a man's voice called from the mist, "Is that the Dover mail?"
"Never you mind what it is!" the guard retorted. "What are you?"
"_Is_ that the Dover mail?"
"Why do you want to know?"
"I want a passenger, if it is."
"What passenger?"
"Mr. Jarvis Lorry."
Our booked passenger showed in a moment that it was his name.
The guard, the coachman, and the two other passengers eyed him distrustfully.

使用正则表达式，我需要在双引号中打印所有内容，我不想要完整的代码，我只需要知道我应该如何去做，哪个正则表达式将是最有用的。 提示和指示，请！

Answer 1

r'(".*?")'将匹配双引号中的每个字符串。 括号表示捕获的组. 匹配每个字符（换行符除外）， *表示重复，而? 使它变得非贪婪（在下一个双引号之前停止匹配）。 如果需要，请在re.DOTALL选项中添加make . 还匹配换行符。

Answer 2

这应该做到（下面有解释）：

from __future__ import print_function

import re

txt = """The sound of a horse at a gallop came fast and furiously up the hill.
"So-ho!" the guard sang out, as loud as he could roar.
"Yo there! Stand! I shall fire!"
The pace was suddenly checked, and, with much splashing and floundering,
a man's voice called from the mist, "Is that the Dover mail?"
"Never you mind what it is!" the guard retorted. "What are you?"
"_Is_ that the Dover mail?"
"Why do you want to know?"
"I want a passenger, if it is."
"What passenger?"
"Mr. Jarvis Lorry."
Our booked passenger showed in a moment that it was his name.
The guard, the coachman, and the two other passengers eyed him distrustfully.
"""

strings = re.findall(r'"(.*?)"', txt)

for s in strings:
    print(s)

结果：

So-ho!
Yo there! Stand! I shall fire!
Is that the Dover mail?
Never you mind what it is!
What are you?
_Is_ that the Dover mail?
Why do you want to know?
I want a passenger, if it is.
What passenger?
Mr. Jarvis Lorry.

r'"(.*?)"'将匹配双引号中的每个字符串。 括号表示捕获组，因此您只会得到不带双引号的文本。 的. 匹配每个字符（换行符除外）， *表示“最后一件事零个或多个”，最后一个是. 。 ? *使得* “非贪婪”，这意味着它匹配的越少越好。 如果您不使用? ，您只会得到一个结果； 一个字符串，其中包含第一个和最后一个双引号之间的所有内容。

您可以包括re.DOTALL标志，以便. 如果要提取与行交叉的字符串，还将匹配换行符。 如果要这样做，请使用re.findall(r'"(.*?)"', txt, re.DOTALL) 。 换行符将包含在字符串中，因此您必须进行检查。

解释不可避免地类似于/基于@ TigerhawkT3的答案。 也投票给那个答案！