[英]how to get positions of non empty values in a dictionary in Python
這是我的字典:
d={"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}
我想要鍵和值為非空值的位置。 我嘗試過:
d.items()
輸出:
[('1', ''), ('3', ''), ('2', ''), ('5', ''), ('4', 'rock'), ('7', 'paper'), ('6', ''), ('8', '')]
我希望我的輸出是:
4 rock
7 paper
請幫忙。
>>> d = {"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}
>>> print {k: v for k, v in d.items() if v}
{'7': 'paper', '4': 'rock'}
像這樣?
d={"1":"", "2":"", "3":"", "4":"rock" , "5":"" , "6":"" ,"7":"paper","8":""}
for key, value in d.items():
if value:
print(key, value)
應該這樣做:
from __future__ import print_function
data = {
'1': '', '2': '', '3': '', '4': 'rock',
'5': '', '6': '', '7': 'paper', '8': '',
}
new_data = {k: v for k, v in data.items() if v}
for k, v in new_data.items():
print(k, v)
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