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將數據表轉換為JSON時出錯

[英]Error when converting datatable to json

將每行的數據表轉換為json時,我沒有得到正確的格式,並且還收到錯誤"RowError":"","RowState":2

這是我的代碼:

 StrQry="select * from doctor_mas where version_code=1";
        DataTable dt=new DataTable();
        dt=Sqlhelper.OleDbTable(StrQry);


        try
        {
            for(int i=0;i<dt.Rows.Count;i++)
            {
             string JSONresult;
             JSONresult = JsonConvert.SerializeObject(dt.Rows[i]);
             var Update = new Salestrak.Update.updDoc();
             String Authrized = Update.updateTable((int)dt.Rows[i][0], "doctor_mas", JSONresult); 
            }
        }
        catch
        {
            MessageBox.Show("Sync Aborted");
        }

結果Json字符串為:

{"RowError":"","RowState":2,"Table":[{"id":248.0,"birth_date":"1950-01-01T00:00:00","doctor_code":"D248","doctor_name":"Ajay A Haryani","version_code":1},{"id":293.0,"birth_date":"1990-05-26T00:00:00","doctor_code":"D293","doctor_name":"Aarti  Thakker","version_code":1}],"ItemArray":[248.0,"1950-01-01T00:00:00","D248","Ajay A Haryani",0,1.0,2.0,"Sandip Palekar","Mumbai-2",2.0,"Vasudhan,1],"HasErrors":false}

嘗試這個:

string JSONresult = JsonConvert.SerializeObject(dt.Rows[i].ItemArray);

基本上,您想序列化DataRow的內容數組。

有一些開銷的替代方法-

var o = JsonConvert.SerializeObject(dt.Rows[0]);

for (var i = 0; i < JObject.Parse(o)["Table"].Count(); i++)
{
    var t = JObject.Parse(o)["Table"][i];
}

來自suresh的博客

// This method is used to convert datatable to json string
public string ConvertDataTabletoString()
{
    DataTable dt = new DataTable();
    using (SqlConnection con = new SqlConnection("Data Source=SureshDasari;Initial Catalog=master;Integrated Security=true"))
    {
        using (SqlCommand cmd = new SqlCommand("select title=City,lat=latitude,lng=longitude,description from LocationDetails", con))
        {
            con.Open();
            SqlDataAdapter da = new SqlDataAdapter(cmd);
            da.Fill(dt);
            System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer();
            List<Dictionary<string, object>> rows = new List<Dictionary<string, object>>();
            Dictionary<string, object> row;
            foreach (DataRow dr in dt.Rows)
            {
                row = new Dictionary<string, object>();
                foreach (DataColumn col in dt.Columns)
                {
                    row.Add(col.ColumnName, dr[col]);
                }
                rows.Add(row);
            }
            return serializer.Serialize(rows);
        }
    }
}

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