將enum作為字符串返回到asp.mvc和json中

Question

我有一個包含enum屬性的類。

我的枚舉：

 public enum ToasterType
    {
        [EnumMember(Value = "success")]
        success,
        [EnumMember(Value = "error")]
        error
    }

我的課 ：

[Serializable]
    public class ToastrMessage
    {
        [JsonConverter(typeof(StringEnumConverter))]
        public ToasterType ToasterType { get; set; }
         // bla bla bla
    }

用Json返回類：

 public async Task<ActionResult> Authentication()
    {
         return Json(this.ToastrMessage(ToasterType.success));
    }

並輸出：

為什么1 ？

但我需要以下內容：

ToasterType: success

Answer 1

如果你只想使用StringEnumConverter進行當前操作，那么你可以在調用json()之前添加以下內容

//convert Enums to Strings (instead of Integer)
JsonConvert.DefaultSettings = (() =>
{
    var settings = new JsonSerializerSettings();
    settings.Converters.Add(new StringEnumConverter { CamelCaseText = true });
    return settings;
});

要全局應用該行為，只需在Global.asax或啟動類中添加以下設置。

HttpConfiguration config = GlobalConfiguration.Configuration;
config.Formatters.JsonFormatter.SerializerSettings.Converters.Add
            (new Newtonsoft.Json.Converters.StringEnumConverter());

Answer 2

使用Json.NET，您可以實現您的需求。 您可以創建一個使用Json.NET而不是默認的ASP.NET MVC JavascriptSerializer的JsonResult派生類：

/// <summary>
/// Custom JSON result class using JSON.NET.
/// </summary>
public class JsonNetResult : JsonResult
{
    /// <summary>
    /// Initializes a new instance of the <see cref="JsonNetResult" /> class.
    /// </summary>
    public JsonNetResult()
    {
        Settings = new JsonSerializerSettings
        {
            ReferenceLoopHandling = ReferenceLoopHandling.Error
        };
    }

    /// <summary>
    /// Gets the settings for the serializer.
    /// </summary>
    public JsonSerializerSettings Settings { get; set; }

    /// <summary>
    /// Try to retrieve JSON from the context.
    /// </summary>
    /// <param name="context">Basic context of the controller doing the request</param>
    public override void ExecuteResult(ControllerContext context)
    {
        if (context == null)
        {
            throw new ArgumentNullException("context");
        }

        if (JsonRequestBehavior == JsonRequestBehavior.DenyGet &&
            string.Equals(context.HttpContext.Request.HttpMethod, "GET", StringComparison.OrdinalIgnoreCase))
        {
            throw new InvalidOperationException("JSON GET is not allowed");
        }

        HttpResponseBase response = context.HttpContext.Response;
        response.ContentType = string.IsNullOrEmpty(ContentType) ? "application/json" : ContentType;

        if (ContentEncoding != null)
        {
            response.ContentEncoding = ContentEncoding;
        }

        if (Data == null)
        {
            return;
        }

        var scriptSerializer = JsonSerializer.Create(Settings);

        using (var sw = new StringWriter())
        {
            scriptSerializer.Serialize(sw, Data);
            response.Write(sw.ToString());
        }
    }
}

然后，在Controller中使用此類來返回數據：

public JsonResult Index()
{
    var response = new ToastrMessage { ToasterType = ToasterType.success };

    return new JsonNetResult { Data = response, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}

通過這種方式，您可以獲得所需的結果：

{ ToasterType: "success" }

請注意，這個解決方案是基於這篇文章 ，所以學分是為作者:)