[英]How to remove multiple elements from multidimensional array with filter in JavaScript?
我們可以使用以下filter
函數從數組中過濾出單個值:
var possi = [
['1','2','3'], ['4','5','6'], ['7','8','9'], ['1','4','7'],
['2','5','8'], ['3','6','9'], ['1','5','9'], ['3','5','7']
];
var remove = '1';
possi = possi.filter(function(p){
return p.indexOf(remove) === -1;
});
結果是:
[ [ '4', '5', '6' ],
[ '7', '8', '9' ],
[ '2', '5', '8' ],
[ '3', '6', '9' ],
[ '3', '5', '7' ] ]
但是,如果我們有多個要刪除的元素,那就是,如果我們有:
var remove = ['1', '6'];
我們如何檢查possi
是否存在每個remove
元素並過濾出匹配的possi
元素?
另外,在這種情況下,諸如map
或reduce
類的其他功能是否是更好的解決方案?
如果要刪除possi
中與array remove
任何元素匹配的所有數組,則可以將Array.prototype.filter()
與Array.prototype.some()
結合使用:
var possi = [ ['1', '2', '3'], ['4', '5', '6'], ['7', '8', '9'], ['1', '4', '7'], ['2', '5', '8'], ['3', '6', '9'], ['1', '5', '9'], ['3', '5', '7'] ]; var remove = ['1', '6']; possi = possi.filter(function(p) { return !p.some(function(v) { return remove.indexOf(v) !== -1; }); }); console.log(possi);
結果是:
[
['7', '8', '9'],
['2', '5', '8'],
['3', '5', '7']
]
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