[英]How to filter multidimensional JavaScript array
我有這個數據:
var object = [{
"nid": "31",
"0": {
"tid": "20",
"name": "Bench Press",
"objectDate": "2012-02-08",
"goal": "rep",
"result": "55.00",
"comments": "sick!",
"maxload": "250"
},
"1": {
"tid": "22",
"name": "Back Squat",
"objectDate": "2012-02-08",
"goal": "time",
"result": "8.00",
"comments": "i was tired.",
"maxload": "310"
}},
{
"nid": "30",
"0": {
"tid": "19",
"name": "Fran",
"objectDate": "2012-02-07",
"goal": "time",
"result": "5.00",
"comments": null
}}];
我想按名稱過濾它。 例如,如果我為名稱“Fran”應用過濾器,我想要這樣的東西:
[0] => Array
(
[tid] => 19
[name] => Fran
[objectDate] => 2012-02-07
[goal] => time
[result] => 5.00
[comments] =>
)
[1] => Array
(
[tid] => 19
[name] => Fran
[objectDate] => 2012-02-08
[goal] => rep
[result] => 55.00
[comments] => woohoo!
)
有可能實現嗎?
Javascript 中沒有此功能。 您必須像這樣編寫自己的函數。
var arr = [{"nid":"31","0":{"tid":"20","name":"Bench Press","objectDate":"2012-02-08","goal":"rep","result":"55.00","comments":"sick!","maxload":"250"},"1":{"tid":"22","name":"Back Squat","objectDate":"2012-02-08","goal":"time","result":"8.00","comments":"i was tired.","maxload":"310"}},{"nid":"30","0":{"tid":"19","name":"Fran","objectDate":"2012-02-07","goal":"time","result":"5.00","comments":null}}];
function filterByProperty(array, prop, value){
var filtered = [];
for(var i = 0; i < array.length; i++){
var obj = array[i];
for(var key in obj){
if(typeof(obj[key] == "object")){
var item = obj[key];
if(item[prop] == value){
filtered.push(item);
}
}
}
}
return filtered;
}
var byName = filterByProperty(arr, "name", "Fran");
var byGoal = filterByProperty(arr, "goal", "time");
問題是關於多維數組。 如果你像我一樣錯過了這里是普通陣列的解決方案......
2020年
filteredArray = array.filter(item => item.name.indexOf('Fran') > -1);
要么
filteredArray = array.filter(function(item)
{
return item.name.indexOf('Fran') > -1);
}
2012版
var result = [];
for (var i = 0; i < array.length; i++)
{
if (array[i].name === 'Fran')
{
result.push(array[i]);
}
}
我會創建一個過濾函數:
function filter(array, key, value){
var i, j, hash = [], item;
for(i = 0, j = array.length; i<j; i++){
item = array[i];
if(typeof item[key] !== "undefined" && item[key] === value){
hash.push(item);
}
}
return hash;
}
一個更強大的解決方案可能是在原型中添加一個過濾器方法:
`This prototype is provided by the Mozilla foundation and
is distributed under the MIT license.
http://www.ibiblio.org/pub/Linux/LICENSES/mit.license`
if (!Array.prototype.filter)
{
Array.prototype.filter = function(fun /*, thisp*/)
{
var len = this.length;
if (typeof fun != "function")
throw new TypeError();
var res = new Array();
var thisp = arguments[1];
for (var i = 0; i < len; i++)
{
if (i in this)
{
var val = this[i]; // in case fun mutates this
if (fun.call(thisp, val, i, this))
res.push(val);
}
}
return res;
};
}
然后只需調用:
function filterName (item, index, array) {
return (item.name === "Fran");
}
var result = object.filter(filterName);
如果您的對象包含 3 個字段,例如電子郵件、名字、姓氏,那么您可以使用它。
ArrayObject
.filter(em => em.email.indexOf(searchEmail) > -1)
.filter(fn => fn.firstName.indexOf(searchFirstName) > -1)
.filter(ln => ln.lastName.indexOf(searchLastName) > -1)
最大的技巧是制作一個平面數組,其中只包含您想要的項目。
假設你有一個像這樣的二維數組:
e = [[1,2],[1,2],[2,3],[4,5],[6,7]]
你創建一個新數組:
var f = []
只用 1 項填充它:
for(var x=0;x<e.length;x++) f[x] = e[x][1]
給我們喜歡:
f = [2,2,3,5,7]
接着....
var g = e.filter( function(elem, pos){ return (f.indexOf(elem[1]) == pos) })
哇!
我嘗試了 Diode 的解決方案。 我適應我的情況。 包含 3 個數組。
var arr =
[
{
taskTypeGroupId: "EXP.CONT", taskTypeGroupName: "Contradictoire",
taskType:
{
taskTypeId: "DGE-EXPCONT", taskTypeName: "Dégats des eaux contradictoire", defaultDuration: 60, isInProject: false,
dataItems:
{
id: "EXTRAFILLER5", label: "Divers 5"
}
}
},
{
takTypeGroupId: "EXPQUAL", taskTypeGroupName: "Contrôle qualité",
taskType:
{
taskTypeId: "DGE-EXPQUAL", taskTypeName: "Contrôle qualité dégats des eaux", defaultDuration: 60, isInProject: false,
dataItems:
{
id: "EXTRAFILLER5", label: "Divers 5"
}
}
}
];
function filterByProperty(array, prop, value){
var filtered = [];
for(var i = 0; i < array.length; i++){
var array1 = array[i];
for(var key in array1){
if(typeof(array1[key] == "object")){
var array2 = array1[key];
for (var key2 in array2){
if(typeof(array2[key2] == "object")){
var array3 = array2[key2];
if(array3[prop] == value){
filtered.push(array3);
}
}
}
}
}
}
return filtered;
}
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