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[英]How to change UPDATE behavior in Spring Data JPA/Hibernate for specific field?
[英]How to update data with Hibernate and Spring JPA in Spring MVC
首先,我只是一個初學者,喜歡學習Spring框架。 我正在使用帶有Hibernate
和Spring JPA
Spring MVC
創建簡單的在線國內航班預訂系統。 當我要更新注冊用戶的姓名,電子郵件和聯系方式時,會出現此問題。
my-profile.jsp(update-user.jsp的鏈接)
<a href='<spring:url value="/account/my-profile/${user.id}.html"/>'>
<button type="button">My Profile</button>
</a>
update-user.jsp
<form:form modelAttribute="userUpdate" method="POST" cssClass="userValidation" >
<div>
<label for="name">Name</label>
<div>
<form:input path="name" name="name"/>
<form:errors path="name"/>
</div>
</div>
<div>
<label for="email">Email</label>
<div class="col-sm-10">
<form:input path="email" name="email"/>
<form:errors path="email"/>
</div>
</div>
<div>
<label for="contactNum">Contact No</label>
<div>
<form:input path="contactNum" name="contactNum"/>
<form:errors path="contactNum"/>
</div>
</div>
</form:form>
UserController.java
@RequestMapping(value="/account/my-profile/{id}", method={RequestMethod.POST})
public String showProfile(@PathVariable int id, ModelMap model,
@Valid @ModelAttribute("userUpdate") User user,
@ModelAttribute("user") User user2,
BindingResult result,Authentication authentication){
if(result.hasErrors()){
return "my-profile";
}
String name = authentication.getName();
User user3 = userService.findOne(name);
userService.save(user3);
return "redirect://flightInfos/booknow/payments.html?success=true";
}
UserService.java
public void save(User user) {
user.setEnabled(true);
BCryptPasswordEncoder encoder = new BCryptPasswordEncoder();
user.setPassword(encoder.encode(user.getPassword()));
List<Role> roles = new ArrayList<Role>();
roles.add(roleRepository.findByName("ROLE_USER"));
user.setRoles(roles);
userRepository.save(user);
}
public User findOne(String name) {
return userRepository.findByName(name);
}
UserRepository.java
public interface UserRepository extends JpaRepository<User, Integer> {
User findByName(String name);
}
當我運行此命令時,沒有錯誤存在,並且控制台中顯示以下sql
語句。
Hibernate: select user0_.id as id1_4_, user0_.contactNum as contactN2_4_, user0_.email as email3_4_, user0_.enabled as enabled4_4_, user0_.name as name5_4_, user0_.password as password6_4_, user0_.userId as userId7_4_ from myUser user0_ where user0_.name is null
Hibernate: select user0_.id as id1_4_, user0_.contactNum as contactN2_4_, user0_.email as email3_4_, user0_.enabled as enabled4_4_, user0_.name as name5_4_, user0_.password as password6_4_, user0_.userId as userId7_4_ from myUser user0_ where user0_.email is null
Hibernate: select user0_.id as id1_4_, user0_.contactNum as contactN2_4_, user0_.email as email3_4_, user0_.enabled as enabled4_4_, user0_.name as name5_4_, user0_.password as password6_4_, user0_.userId as userId7_4_ from myUser user0_ where user0_.name=?
Hibernate: select user0_.id as id1_4_, user0_.contactNum as contactN2_4_, user0_.email as email3_4_, user0_.enabled as enabled4_4_, user0_.name as name5_4_, user0_.password as password6_4_, user0_.userId as userId7_4_ from myUser user0_ where user0_.email=?
Hibernate: select user0_.id as id1_4_, user0_.contactNum as contactN2_4_, user0_.email as email3_4_, user0_.enabled as enabled4_4_, user0_.name as name5_4_, user0_.password as password6_4_, user0_.userId as userId7_4_ from myUser user0_ where user0_.name=?
Hibernate: select role0_.id as id1_3_, role0_.name as name2_3_ from Role role0_ where role0_.name=?
Hibernate: update myUser set contactNum=?, email=?, enabled=?, name=?, password=?, userId=? where id=?
Hibernate: delete from myUser_Role where users_id=?
Hibernate: insert into myUser_Role (users_id, roles_id) values (?, ?)
當我運行該程序時,數據庫中沒有任何更改。 而且我也無法使用新憑據或以前的憑據進行日志記錄。
感謝您為查明此案提供的幫助。 我需要更新現有用戶。 他的姓名,電子郵件和聯系方式。 我該怎么辦才能解決這個問題?
Role
實體
@Entity
public class Role {
@Id
@GeneratedValue
private Integer id;
private String name;
@ManyToMany(mappedBy="roles")
private List<User> users;
getters and setters
User
實體
@Entity
@Table(name = "myUser")
public class User {
@Id
@GeneratedValue
private Integer id;
private String userId;
@Size(min=4, message="Name must be at least 4 characters.")
@UniqueUsername(message="Username exists")
@Column(unique=true)
private String name;
@Size(min=5, message="Password must be at least 5 characters.")
private String password;
@Size(min=1, message="Invalid email")
@Email(message="Invalid email")
@UniqueEmail(message="Email exists")
private String email;
private String contactNum;
private Boolean enabled;
@ManyToMany
@JoinTable
private List<Role> roles;
getters & setters
您在哪里更新? 在您的控制器中,您只是從db中獲取用戶,然后立即保存它。
User user3 = userService.findOne(name); userService.save(user3);
您應該使用新數據更新user3。 我會這樣做。
User user3 = userService.findOne(name); updateUser(user3, user); userService.save(user3);
updateUser方法:
private void updateUser(oldUser, newUser){ oldUser.setName(newUser.getName()); oldUser.setEmail(newUser.getEmail()); oldUser.setContactNum(newUser.getContactNum()) }
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