[英]Read double from xml file with XMLReader
我有一個使用以下代碼使用XMLWriter創建的簡單XML文件:
using (XmlWriter writer = XmlWriter.Create("c:\\temp\\data.xml"))
{
writer.WriteStartElement("ScaleFactors");
writer.WriteStartAttribute("CorrectionFactorX");
writer.WriteValue(CorrectionFactorX);
writer.WriteEndAttribute();
writer.WriteStartAttribute("CorrectionFactorY");
writer.WriteValue(CorrectionFactorY);
writer.WriteEndAttribute();
writer.WriteStartAttribute("CorrectionFactorZ");
writer.WriteValue(CorrectionFactorZ);
writer.WriteEndAttribute();
writer.WriteEndElement();
writer.Flush();
}
XML文件如下所示:
<?xml version="1.0" encoding="utf-8"?>
<ScaleFactors CorrectionFactorX="1"
CorrectionFactorY="1"
CorrectionFactorZ="1" />
(CorrectionFactorX / Y / Z是雙精度型)現在我想用XMLReader讀回它們,但是失敗了。 我嘗試過MoveToAttribute / GetAttribute沒有成功。 任何提示和代碼示例,不勝感激。
謝謝!
如果可以使用XDoc
void Main()
{
var xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><ScaleFactors CorrectionFactorX=\"1.31\" CorrectionFactorY=\"1\" CorrectionFactorZ=\"1\" />";
var xdoc = XDocument.Parse(xml);
var cfx = Double.Parse(xdoc.Element("ScaleFactors").Attribute("CorrectionFactorX").Value);
Console.WriteLine (cfx);
}
如果您堅持使用XmlReader,則
void Main()
{
var xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><ScaleFactors CorrectionFactorX=\"1.31\" CorrectionFactorY=\"1\" CorrectionFactorZ=\"1\" />";
using (var reader = XmlReader.Create(new StringReader(xml)))
{
while (reader.Read())
{
if (reader.NodeType == XmlNodeType.Element)
{
Console.WriteLine(reader.Name);
var attc = reader.AttributeCount;
for (int i = 0; i < attc; i++)
{
Console.WriteLine(reader.GetAttribute(i));
}
}
}
}
}
(在MSDN上處理XML的不同部分的好例子,但是使用XDocument
會更好)
使用XmlDocument-
var xml = new XmlDocument();
xml.Load("xmlPath");
var match = xml.DocumentElement.Attributes;
foreach (XmlAttribute item in match)
{
Console.WriteLine(item.Value);
}
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