Python-遍歷列表A和匹配列表B中包含的單詞

Question

假設我有兩個列表：

foo = ['hell', 'good', 'bad']
bar = ['hello', 'goodbye', 'goodness', 'badly', 'baddest']

我想對foo進行排序，看看bar中是否有任何單詞不僅匹配而且包含foo，以獲得類似以下內容：

hell = hello
good = goodbye goodness
bad = badly baddest

Answer 1

one = ['hell','good','bad']
two = ['hello', 'goodbye', 'goodness', 'badly', 'baddest']

for a in one:
    print a,'=',
    for b in two:
        if a in b:
            print b,
    print

輸出：

hell = hello
good = goodbye goodness
bad = badly baddest

Answer 2

非常簡單的問題，有很多解決方法。 如果沒有匹配項，則此版本不會打印出“等於”行：

foo = ["hell", "good", "bad", "fail"]
bar = ["hello", "goodbye", "goodness", "badly", "baddest", "nomatch"]

for f in foo:
    matches = [b for b in bar if f in b]
    if len(matches) > 0:
        print(f,"="," ".join(matches))

輸出：

hell = hello
good = goodbye goodness
bad = badly baddest

請注意，它不會輸出“失敗”。 如果您希望它打印單詞“ fail”，請刪除if語句。 甚至可以將代碼減少到一行，盡管我認為這是非常難以理解的一行：

[print(f,"="," ".join(b for b in bar if f in b)) for f in foo]