[英]Convert a binary to an array with each binary number
我正在嘗試將每個1/0的二進制值轉換為列表,但是我得到默認的二進制值而不是列表。
我有一個字符串,我將每個字符轉換為二進制,它為我提供了一個列表,其中包含每個字符的字符串。 現在,我試圖將每個字符串拆分為值0/1的整數,但是我什么也沒得到。
# if message = "CC"
message="CC"
# just a debug thing
for c in message:
asci = ord(c)
bin = int("{0:b}".format(asci))
print >> sys.stderr, "For %c, asci is %d and bin is %d" %(c,asci,bin)
c = ["{0:b}".format(ord(c)) for c in message]
# c = ['1000011', '1000011']
bin = [int(c) for c in c]
#bin should be [1,0,0,0,0,1,1,1,0,0,0,0,1,1]
# but I get [1000011, 1000011]
print >> sys.stderr, bin
如果您有這個:
c = ['1000011', '1000011']
您想要實現以下目標:
[1,0,0,0,0,1,1,1,0,0,0,0,1,1]
你可以做:
modified_list=[int(i) for element in c for i in element]
或者您可以使用itertools.chain
from itertools import chain
modified_list=list(chain(*c))
當您想同時加入列表理解功能時,可以這樣進行:
bin= list( chain( *["{0:b}".format(ord(c)) for c in message] )
嘗試;
bin = [int(x)for s in c for x in s]
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