如何在OpenGL中繪制一個立方體？

Question

我需要幫助。 我發現了幾種在OpenGl中繪制立方體的解決方案，但是我有一個問題。

我的代碼是：

    wglMakeCurrent(pDC->m_hDC, m_hrc);
glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();

glTranslatef(1.5f, 0.0f, -7.0f);  // Move right and into the screen

glBegin(GL_QUADS);                // Begin drawing the color cube with 6 quads
                                  // Top face (y = 1.0f)
                                  // Define vertices in counter-clockwise (CCW) order with normal pointing out
glColor3f(0.0f, 1.0f, 0.0f);     // Green
glVertex3f(1.0f, 1.0f, -1.0f);
glVertex3f(-1.0f, 1.0f, -1.0f);
glVertex3f(-1.0f, 1.0f, 1.0f);
glVertex3f(1.0f, 1.0f, 1.0f);

// Bottom face (y = -1.0f)
glColor3f(1.0f, 0.5f, 0.0f);     // Orange
glVertex3f(1.0f, -1.0f, 1.0f);
glVertex3f(-1.0f, -1.0f, 1.0f);
glVertex3f(-1.0f, -1.0f, -1.0f);
glVertex3f(1.0f, -1.0f, -1.0f);

// Front face  (z = 1.0f)
glColor3f(1.0f, 0.0f, 0.0f);     // Red
glVertex3f(1.0f, 1.0f, 1.0f);
glVertex3f(-1.0f, 1.0f, 1.0f);
glVertex3f(-1.0f, -1.0f, 1.0f);
glVertex3f(1.0f, -1.0f, 1.0f);

// Back face (z = -1.0f)
glColor3f(1.0f, 1.0f, 0.0f);     // Yellow
glVertex3f(1.0f, -1.0f, -1.0f);
glVertex3f(-1.0f, -1.0f, -1.0f);
glVertex3f(-1.0f, 1.0f, -1.0f);
glVertex3f(1.0f, 1.0f, -1.0f);

// Left face (x = -1.0f)
glColor3f(0.0f, 0.0f, 1.0f);     // Blue
glVertex3f(-1.0f, 1.0f, 1.0f);
glVertex3f(-1.0f, 1.0f, -1.0f);
glVertex3f(-1.0f, -1.0f, -1.0f);
glVertex3f(-1.0f, -1.0f, 1.0f);

// Right face (x = 1.0f)
glColor3f(1.0f, 0.0f, 1.0f);     // Magenta
glVertex3f(1.0f, 1.0f, -1.0f);
glVertex3f(1.0f, 1.0f, 1.0f);
glVertex3f(1.0f, -1.0f, 1.0f);
glVertex3f(1.0f, -1.0f, -1.0f);
glEnd();  // End of drawing color-cube

glFlush();                  

SwapBuffers(pDC->m_hDC);
wglMakeCurrent(NULL, NULL);

貝婁是我想要的圖像，也是我得到的圖像。 預期的圖像和我得到的圖像

如何解決這個問題呢？ 提前致謝。

Answer 1

您必須啟用深度測試。 否則，將按照代碼中給定的順序繪制三角形，即使三角形在另一個三角形后面，也會導致過度繪制。 啟用深度測試通話

glEnable(GL_DEPTH_TEST);

在發出第一個抽獎電話之前。