[英]Passing object type in generic method
我正在嘗試實現這一目標,但不知道是否可行。這是一個代碼示例:
public List<Tuple<AbstractPlateforme, AbstractPlateforme>> tuple;
Type type1 = tuple.Item1.GetType();
//This line gives me error: Error CS0118 'type1' is a variable but is used like a type
var plateforme = PlateformeHelper.GetPlateforme<type1>();
//This is my method from my PlateformeHelper class which returns an instance of an instantiated object of the same type (the list may only contain 1 object of that type which inherit from AbstractPlateforme)
public static T GetPlateforme<T>() where T : AbstractPlateforme
{
return (T)ListePlateforme.Find(x => x.GetType() == typeof (T));
}
您應該創建一個接受Type
參數而不是泛型的重載:
public static AbstractPlateforme GetPlateforme(Type type)
{
return (AbstractPlateforme)ListePlateforme.Find(x => x.GetType() == type);
}
public static T GetPlateforme<T>() where T : AbstractPlateforme
{
return (T)GetPlateforme(typeof(T));
}
然后您可以簡單地調用新的重載:
var plateforme = PlateformeHelper.GetPlateforme(type1);
如果您想將反射與泛型一起使用,也許可以幫助您查看下面的代碼:
Type type1 = tuple.Item1.GetType();
MethodInfo method = typeof(PlateformeHelper).GetMethod("GetPlateforme");
MethodInfo generic = method.MakeGenericMethod(type1);
generic.Invoke(null, null);
有關更多信息MakeGenericMethod
希望是有用的XD。
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