[英]Unknown column where clause
我有以下DQL查詢
SELECT
ps.id,
MAX(ps.dueDate) as due_date,
u.firstName as first_name,
u.lastName as last_name,
u.email,
IDENTITY(ps.loanApplication) as loan_application_id,
DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE()) as diff
FROM
Loan\Entity\PaymentSchedule ps
LEFT JOIN
ps.paymentType pt
LEFT JOIN
ps.loanApplication la
LEFT JOIN
la.status s
LEFT JOIN
la.user u
WHERE
pt.slug != :paymentSlug AND s.keyIdentifier = :status AND diff = 14
GROUP BY
ps.loanApplication
轉換為以下SQL查詢
SELECT
p0_.id AS id_0,
MAX(p0_.due_date) AS sclr_1,
u1_.first_name AS first_name_2,
u1_.last_name AS last_name_3,
u1_.email AS email_4,
p0_.loan_application_id AS sclr_5,
DATEDIFF(MAX(p0_.due_date), CURRENT_DATE) AS sclr_6
FROM
payment_schedule p0_
LEFT JOIN
payment_type p2_ ON p0_.payment_type_id = p2_.id
LEFT JOIN
loan_application l3_ ON p0_.loan_application_id = l3_.id
LEFT JOIN
loan_application_status l4_ ON l3_.loan_application_status_id = l4_.id
LEFT JOIN
user u1_ ON l3_.user_id = u1_.id
WHERE
p2_.slug <> ? AND l4_.key_identifier = ? AND sclr_6 = 14
GROUP BY
p0_.loan_application_id
這給我以下錯誤
======================================================================
PDOException
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sclr_6' in 'where clause'
----------------------------------------------------------------------
當我更換WHERE條件時
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status AND diff = 14
用
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status
它可以完美運行並向我顯示正確的記錄,我也嘗試了以下條件
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status AND DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE()) = :days_diff
WHERE pt.slug != :paymentSlug AND s.keyIdentifier = :status HAVING (DATE_DIFF(MAX(ps.dueDate), CURRENT_DATE())) = :days_diff
上面的WHERE也不起作用,我在這里想念什么?
謝謝。
如果要在WHERE子句中使用別名,則需要一個sub-select
。
select *
from
(SELECT
p0_.id AS id_0,
MAX(p0_.due_date) AS sclr_1,
u1_.first_name AS first_name_2,
u1_.last_name AS last_name_3,
u1_.email AS email_4,
p0_.loan_application_id AS sclr_5,
DATEDIFF(MAX(p0_.due_date), CURRENT_DATE) AS sclr_6
FROM
payment_schedule p0_
LEFT JOIN
payment_type p2_ ON p0_.payment_type_id = p2_.id
LEFT JOIN
loan_application l3_ ON p0_.loan_application_id = l3_.id
LEFT JOIN
loan_application_status l4_ ON l3_.loan_application_status_id = l4_.id
LEFT JOIN
user u1_ ON l3_.user_id = u1_.id
) A
WHERE
slug <> ? AND key_identifier = ? AND sclr_6 = 14
這是邏輯上處理查詢的方式
FROM clause
WHERE clause
SELECT clause
GROUP BY clause
HAVING clause
ORDER BY clause
由於Where
Select
之前先出現”,因此您不能在“ Where
子句中使用alias name
您不能在WHERE
子句中使用別名(在最終結果字段中)。 但是,至少在MySQL中,您可以使用HAVING
子句而不需要GROUP BY
。
您使用的表達式是聚合的結果。 替換添加一個having
子句,使查詢看起來像;
SELECT . . .
WHERE p2_.slug <> ? AND l4_.key_identifier = ?
GROUP BY p0_.loan_application_id
HAVING sclr_6 = 14
注意date_diff()
在MySQL中不是一個函數。 您打算使用datediff()
。
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