如何在XML中獲取文本和屬性值

Question

XML范例：

<?xml version="1.0" encoding="utf-8" ?>
<brand name="brand1" num_brand="118" enabled="True">
  <price>
    <nodePattern>pattern</nodePattern>
    <attribute type="text" ></attribute>
    <treatment enabled="1" type="Regex">reg</treatment>
  </price>
  <title>
    <nodePattern>pattern</nodePattern>
    <attribute type="text" ></attribute>
    <treatment enabled="1" type="Regex">reg</treatment>
  </title>
</brand>

請使用System.Xml.Linq如何獲取我所有不同節點的不同屬性值和文本（例如，名稱，num_brand和啟用品牌，啟用，類型和“ reg”進行處理）？

謝謝 ！

Answer 1

System.Xml.Linq命名空間比System.Xml命名空間好得多。 您的XDocument具有一個XElement ，而XElement又具有子元素。 每個元素都有屬性和一個值。

這是給你的一個例子：

var text = @"<?xml version=""1.0"" encoding=""utf-8"" ?>
            <brand name=""brand1"" num_brand=""118"" enabled=""True"">
                <price>
                <nodePattern>pattern</nodePattern>
                <attribute type=""text"" ></attribute>
                <treatment enabled=""1"" type=""Regex"">reg</treatment>
                </price>
                <title>
                <nodePattern>pattern</nodePattern>
                <attribute type=""text"" ></attribute>
                <treatment enabled=""1"" type=""Regex"">reg</treatment>
                </title>
            </brand>";

XDocument document = XDocument.Parse(text);

// one root element - "brand"          
System.Diagnostics.Debug.Assert(document.Elements().Count() == 1);
XElement brand = document.Element("brand");

// brand has two children - price and title           
foreach (var element in brand.Elements())
    Console.WriteLine("element name: " + element.Name);

// brand has three attributes
foreach (var attr in brand.Attributes())
    Console.WriteLine("attribute name: " + attr.Name + ", value: " + attr.Value);

Answer 2

您有很多方法可以做到這一點。 其中之一是XmlDocument。

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(myXML);
foreach(XmlNode node in xmlDoc.DocumentElement.ChildNodes){
    string text = node.InnerText; //you can loop through children
}

看一下這篇文章： 如何在C＃中讀取和解析XML文件？

性格方面，我喜歡Linq To Xml方法，請在此處獲取更多信息： https : //msdn.microsoft.com/en-us/library/bb387061.aspx

Answer 3

嘗試這個

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENMAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENMAME);

            var brand = doc.Descendants("brand").Select(x => new
            {
                name = x.Attribute("name").Value,
                num_brand = x.Attribute("num_brand").Value,
                enabled = x.Attribute("enabled").Value,
                nodePattern = x.Element("price").Element("nodePattern").Value,
                attribute = x.Element("price").Element("attribute").Attribute("type").Value,
                priceTreatmentEnable = x.Element("price").Element("treatment").Attribute("enabled").Value,
                priceTreatmentType = x.Element("price").Element("treatment").Attribute("type").Value,
                priceTreatment = x.Element("price").Element("treatment").Value,
                titleTreatmentEnable = x.Element("title").Element("treatment").Attribute("enabled").Value,
                titleTreatmentType = x.Element("title").Element("treatment").Attribute("type").Value,
                titleTreatment = x.Element("title").Element("treatment").Value
            }).FirstOrDefault();
        }
    }
}
​