![](/img/trans.png)
[英]spring http error 400 The request sent by the client was syntactically incorrect
[英]Error “400 Bad Request” The request sent by the client was syntactically incorrect
我是jQuery的新手,並嘗試使用Ajax調用Web服務。 看起來很簡單的代碼,但是某種程度上無法理解其失敗的原因。 我嘗試了所有可能的方法(我能想到的),但是不知怎么使它無法工作。
Jsp代碼:
function tmpData() {
var dataObject = JSON.stringify({
'empfname': "First Name",
'emplname': "Last Name"
});
alert("dataObject=" + dataObject);
$.ajax({
url:"http://localhost:8080/OnlineStore/kmsg/grocery/tmpinfo",
type:"POST",
contentType: 'application/json',
data: dataObject,
done: setData,
fail: displayError()
});
}; // end of function
控制器:
@RestController
@RequestMapping("/kmsg/grocery")
public class TmpSvcImpl implements TmpSvcInt {
@Override
@RequestMapping(value = "/tmpinfo", method = RequestMethod.POST, headers = "Accept=application/json")
public @ResponseBody Map<String, Object> setData(@RequestBody final Emp employee1) throws Exception {
System.out.println("employee1=" + employee1);
String fname = employee1.getEmpfname();
String lname = employee1.getEmplname();
System.out.println("fn=" + fname ) ;
System.out.println("ln=" + lname ) ;
return null;
}
}
型號類別:
public class Emp implements Serializable {
private static final long serialVersionUID = 1L;
String empfname;
String emplname;
public String getEmpfname() {
return empfname;
}
public void setEmpfname(String empfname) {
this.empfname = empfname;
}
public String getEmplname() {
return emplname;
}
public void setEmplname(String emplname) {
this.emplname = emplname;
}
public Emp(String fn, String ln){
this.empfname = fn ;
this.emplname = ln ;
}
@Override
public String toString() {
return "Emp {empfname=" + empfname + ", emplname=" + emplname + "}" ;
}
}
在該塊中,您描述了:
@RestController
@RequestMapping("/kmsg/grocery")
public class TmpSvcImpl implements TmpSvcInt {
@Override
@RequestMapping(
value = "/tmpinfo",
method = RequestMethod.POST,
headers = "Accept=application/json")
public @ResponseBody Map<String, Object> setData(@RequestBody final Emp employee1) throws Exception {
System.out.println("employee1=" + employee1);
String fname = employee1.getEmpfname();
String lname = employee1.getEmplname();
System.out.println("fn=" + fname ) ;
System.out.println("ln=" + lname ) ;
return null;
}
}
為這種使用情況指定“ Accept”標頭並不是真正正確的。 如果要讓此方法僅在content-type為'application / json'時響應,則必須添加一個消費屬性'application / json'。 正如評論指出的那樣,這並非絕對必要。 添加Produce屬性'application / json'將確保Spring嘗試將返回的內容編組為JSON結構。
@RestController
@RequestMapping("/kmsg/grocery")
public class TmpSvcImpl implements TmpSvcInt {
@Override
@RequestMapping(
value = "/tmpinfo",
method = RequestMethod.POST,
consumes = "application/json",
produces = "application/json")
public @ResponseBody Map<String, Object> setData(@RequestBody final Emp employee1) throws Exception {
System.out.println("employee1=" + employee1);
String fname = employee1.getEmpfname();
String lname = employee1.getEmplname();
System.out.println("fn=" + fname ) ;
System.out.println("ln=" + lname ) ;
return null;
}
}
將默認構造函數添加到Emp
類,以便Jackson
可以創建它的實例,如下所示:
public class Emp implements Serializable {
private static final long serialVersionUID = 1L;
public String empfname;
public String emplname;
public String getEmpfname() {
return empfname;
}
public void setEmpfname(String empfname) {
this.empfname = empfname;
}
public String getEmplname() {
return emplname;
}
public void setEmplname(String emplname) {
this.emplname = emplname;
}
public Emp(String fn, String ln) {
this.empfname = fn;
this.emplname = ln;
}
/**
* default constructor
*/
public Emp() {
}
@Override
public String toString() {
return "Emp {empfname=" + empfname + ", emplname=" + emplname + "}";
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.