根據貸記和借記記錄計算余額

Question

我的數據庫表中有以下記錄：

Date            Credit  Debit      Description
--------------- ------- -------    ---------------
12-24-2015      5                  Purchased credit
12-20-2015              1          Consumed credit
12-15-2015      3                  Purchased credit
12-08-2015              1          Consumed credit
12-08-2015              1          Consumed credit
12-07-2015              1          Consumed credit
12-04-2015              1          Consumed credit
12-03-2015              1          Consumed credit
12-01-2015      5                  Purchased credit

我想計算並顯示每條記錄的余額，如下所示：

Date         Credit  Debit   Balance  Description
------------ ------- ------- -------  ---------------
12-24-2015   5       0       7        Purchased credit
12-20-2015           1       2        Consumed credit
12-15-2015   3       0       3        Purchased credit
12-08-2015           1       0        Consumed credit
12-08-2015           1       1        Consumed credit
12-07-2015           1       2        Consumed credit
12-04-2015           1       3        Consumed credit
12-03-2015           1       4        Consumed credit
12-01-2015   5       0       5        Purchased credit

任何人都可以幫助我實現上述結果嗎？

Answer 1

要生成余額，請在分析版本中使用sum() 。

select tdate, credit, debit, 
       sum(nvl(credit, 0)-nvl(debit, 0)) over (order by rn) balance, description
  from (
    select tdate, credit, debit, row_number() over (order by tdate) rn, description 
      from test)
  order by rn desc

如果您的表包含增加的主鍵，您可以使用它而不是生成的行號。

測試數據和輸出：

create table test (tdate date, credit number(6), debit number(6), description varchar2(20));
insert into test values (date '2015-12-24', 5, null, 'Purchased credit');
insert into test values (date '2015-12-20', null, 1, 'Consumed credit');
insert into test values (date '2015-12-15', 3, null, 'Purchased credit');
insert into test values (date '2015-12-08', null, 1, 'Consumed credit');
insert into test values (date '2015-12-08', null, 1, 'Consumed credit');
insert into test values (date '2015-12-07', null, 1, 'Consumed credit');
insert into test values (date '2015-12-04', null, 1, 'Consumed credit');
insert into test values (date '2015-12-03', null, 1, 'Consumed credit');
insert into test values (date '2015-12-01', 5, null, 'Purchased credit');

TDATE        CREDIT   DEBIT    BALANCE DESCRIPTION
----------- ------- ------- ---------- --------------------
2015-12-24        5                  7 Purchased credit
2015-12-20                1          2 Consumed credit
2015-12-15        3                  3 Purchased credit
2015-12-08                1          0 Consumed credit
2015-12-08                1          1 Consumed credit
2015-12-07                1          2 Consumed credit
2015-12-04                1          3 Consumed credit
2015-12-03                1          4 Consumed credit
2015-12-01        5                  5 Purchased credit

Answer 2

您應該能夠為此使用LAG分析函數來查看前一行的數據。

SELECT Date, 
       Credit, 
       Debit, 
       LAG(Balance, 1, 0) OVER(ORDER BY Date) - Debit + Credit AS Balance, 
       Description
  FROM sometable

1參數表示它看起來在前 1 行， 0參數表示如果給定偏移處的行不存在，它將返回 0（即第一行）。

來源： https ://oracle-base.com/articles/misc/lag-lead-analytic-functions

Answer 3

試試這個，首先進行自連接，然后按順序列出結果：

SELECT a1.Date, a1.Debit, a1.Credit, SUM(a2.Debit-a2.Credit) Balance, Description
FROM table a1, table a2
WHERE a1.debit<=a2.debit and a1.credit<=a2.credit OR (a1.debit=a2.debit and a1.credit=a2.credit and a1.date = a2.date)
GROUP BY a1.Date, a1.Debit, a1.Credit
ORDER BY a1.Date DESC;

Answer 4

對於誰可能會看到mssql的這個問題，你可以使用這個查詢：

select tdate, credit, debit, 
       sum(isnull(credit, 0)-isnull(debit, 0)) over (order by rn) balance, description
  from (
    select tdate, credit, debit, row_number() over (order by tdate) rn, description 
      from test)
  order by rn desc