如何在SQL Server中計算借方和貸方余額？

Question

我有桌子：

• 客戶（Id_Customer，姓名，地址）

    (1,A, Add1) (2,B, Add2) (3,C, Add3) (4,D, Add4) (5,E, Add5) 

• 收據（Id_Customer，資金）

    (2, 10) (3, 20) (2, 15) 

• 付款（Id_Customer，資金）

    (1, 30) (2, 40) (4, 05) 

現在，我想顯示如下：

Name   -------   Debit balance  ------    In credit    
A       ----------------------------------------30

B ----------------15-------------------------

C    -----------------------------------------20

D  -------------- 05-----------------------


Total DB: -----   20-------------Total IC: 50

在那里面：

if sum(money) of Receipt < sum(money) of Payment 
   then Debit balance = sum(money) of Payment - sum(money) of Receipt 
else 
   In credit = sum(money) of Receipt-sum(money) of Payment

請注意，僅在“借方余額”或“貸方”不為零時顯示“客戶”。 並且總計超過（）進行分頁。

我使用QUERY運行，但僅在兩個表中顯示“錢”的客戶收據和付款（如果客戶只有收據中有錢，否則付款不會顯示結果，為什么？不能顯示該客戶？）

select a.*, Total_DebitBalance=sum(DebitBalance) over (), Total_InCredit=sum(InCredit) over () from (SELECT C.name, C.Address,

CASE WHEN SUM(isnull(R.Money, 0))< SUM(isnull(P.Money, 0)) THEN SUM(isnull(P.Money, 0)) - SUM(isnull(R.Money, 0)) END AS DebitBalance,

CASE WHEN SUM(isnull(R.Money, 0))> SUM(isnull(P.Money, 0)) THEN SUM(isnull(R.Money, 0)) - SUM(isnull(P.Money, 0)) END AS InCredit,

C.Id_Customer, COUNT(*) OVER () AS total_count

FROM Customer C LEFT JOIN Receipt R ON C.Id_Customer = R.Id_Customer LEFT JOIN Payment P ON C.Id_Customer = P.Id_Customer group by C.Id_Customer, C.name, C.Address)a ;

結果如下：

名稱-------借方余額------貸方

B ----------------15-------------------------

Total DB: -----   15-------------Total IC: 0

Answer 1

修改后的查詢。 （不好意思推遲了）

以下應滿足您的需求

SELECT 
    C.Id_Customer,
    CASE 
       WHEN ISNULL(R.[Money], 0) - ISNULL(P.[Money], 0)> 0 
          THEN ISNULL(R.[Money], 0) - ISNULL(P.[Money], 0)
    END AS [Debit balance],
    CASE 
       WHEN ISNULL(P.[Money], 0) - ISNULL(R.[Money], 0) > 0 
          THEN ISNULL(P.[Money], 0) - ISNULL(R.[Money], 0)
    END AS [In credit]

FROM
    Customer C
LEFT JOIN 
    (SELECT SUM([Money]) AS [Money],Id_Customer FROM Receipt GROUP BY Id_Customer) R ON C.Id_Customer = R.Id_Customer
LEFT JOIN 
    (SELECT SUM([Money]) AS [Money],Id_Customer FROM Payment GROUP BY Id_Customer)P ON C.Id_Customer = P.Id_Customer