[英]Aggregate values in data frame based on an array of start and end dates - R
示例數據:
Date_End <- c("1999-08-30","1999-09-07","1999-09-20","1999-09-27","1999-10-04","1999-10-12")
Date_Start <- c("1999-08-24" ,"1999-08-30" ,"1999-09-13" ,"1999-09-20" ,"1999-09-27" ,"1999-10-04")
as.Date(Date_Start, "%Y-%m-%d" )
as.Date(Date_End, "%Y-%m-%d" )
df1 <- data.frame(Date_Start,Date_End)
c1 <- data.frame(seq(as.Date('1999-08-24'), as.Date('1999-10-12'), by = 1))
c2 <- sample(100, size = nrow(c1), replace = TRUE)
df2 <- data.frame(c2,c1)
names(df2) <- c("unit","date")
df2 <- zoo(df2)
我在df1
有一個開始和結束日期數組,在df2
有一個時間序列。 我想使用聚合函數(主要是求和),以便在df1
每一行中獲得df2
中unit
總和。 例如,產生如下內容:
Date_Start Date_End sum(unit)
8/24/1999 8/30/1999 282
8/30/1999 9/7/1999 269
9/13/1999 9/20/1999 464
9/20/1999 9/27/1999 308
9/27/1999 10/4/1999 408
10/4/1999 10/12/1999 353
我試過同時使用兩個窗口函數:
window(df2,start = df1$Date_Start, end = df1$Date_End)
並創建一個序列,然后進行索引:
seq_a <- seq(as.Date(df1$Date_Start), as.Date(df1$Date_End), by = 1) test <- df2[seq_a] sum(test)
但是,使用seq時,您只能有一個起點和終點:
Error in seq.Date(as.Date(df1$Date_Start), as.Date(df1$Date_End), by = 1) :
'from' must be of length 1
幫助贊賞!
可能應該使用函數而不是循環,但是為了快速又骯臟,您可以執行以下操作:
Date_End <- c("1999-08-30","1999-09-07","1999-09-20","1999-09-27","1999-10-04","1999-10-12")
Date_Start <- c("1999-08-24" ,"1999-08-30" ,"1999-09-13" ,"1999-09-20" ,"1999-09-27" ,"1999-10-04")
Date_Start <- as.Date(Date_Start, "%Y-%m-%d" )
Date_End <- as.Date(Date_End, "%Y-%m-%d" )
df1 <- data.frame(Date_Start,Date_End)
c1 <- data.frame(seq(as.Date('1999-08-24'), as.Date('1999-10-12'), by = 1))
c2 <- sample(100, size = nrow(c1), replace = TRUE)
df2 <- data.frame(c2,c1)
names(df2) <- c("unit","date")
for (i in 1:nrow(df1)) {
df1$sum[i] <- sum(df2$unit[df2$date > df1$Date_Start[i] & df2$date < df1$Date_End[i]])
}
注意我也修改了代碼的第3行和第4行。
此解決方案不能將df2
用作zoo
對象,但它可能仍對您有用:
Date_End <- as.Date(c("1999-08-30","1999-09-07","1999-09-20","1999-09-27","1999-10-04","1999-10-12"))
Date_Start <- as.Date(c("1999-08-24" ,"1999-08-30" ,"1999-09-13" ,"1999-09-20" ,"1999-09-27" ,"1999-10-04"))
df1 <- data.frame(Date_Start,Date_End)
c1 <- seq(as.Date('1999-08-24'), as.Date('1999-10-12'), by = 1)
c2 <- sample(100, size = length(c1), replace = TRUE)
df2 <- data.frame(unit = c2, date = c1)
library(sqldf)
> sqldf("select Date_Start, Date_End, sum(unit) as units
from df1,
df2
where df1.Date_Start <= df2.date
and df2.date <= df1.Date_end
group by Date_Start")
Date_Start Date_End units
1 1999-08-24 1999-08-30 258
2 1999-08-30 1999-09-07 493
3 1999-09-13 1999-09-20 423
4 1999-09-20 1999-09-27 432
5 1999-09-27 1999-10-04 433
6 1999-10-04 1999-10-12 584
我編輯了一些代碼,包括使Date_Start
和Date_End
日期對象和c1
成為矢量,而不是data.frame。
PS不建議使用帶下划線的案例,這是樣式指南 。
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