[英]Generic interface/base class - access members without type constraints
假設我有一個如下所示的類結構:
public abstract class MyOtherBaseClass
{
public string HelloWorld;
}
public interface MyInterface<T> where T : MyOtherBaseClass
{
T MyObject { get; set; }
}
public abstract class MyBaseClass<T> : MyInterface<T>
where T : MyOtherBaseClass
{
public T MyObject { get; set; }
}
public class MyImplementation : MyBaseClass<MyOtherBaseClass>
{
}
有什么方法可以在MyBaseClass
任何實現中訪問MyObject
嗎? 我不能使用MyBaseClass
或MyInterface
變量,因為我必須指定類型約束,但就我而言,我對指定它們不感興趣,因為我要做的就是訪問其中的值。
理想情況下,我希望能夠執行以下操作:
MyBaseClass baseObject = null;
if(someCondition)
{
baseObject = new MyImplementation();
}
else if(otherCondition)
{
baseObject = new OtherImplementation(); //this also inherits from MyBaseClass
}
var objectValue = baseObject.MyObject;
var helloWorldValue = objectValue.HelloWorld;
您想要的不是完全不可能的,不是泛型的。 類型MyBaseClass
根本不存在。 泛型類型必須具有泛型類型參數。
如果您不想使用泛型,為什么要使用泛型?
這也可能是有效的選擇:
public interface MyInterface
{
object MyObject { get; set; }
}
public abstract class MyBaseClass : MyInterface
{
public object MyObject { get; set; }
}
當然,在此示例中,您必須將對象轉換為特定類型。
您還可以結合兩種技術:
public interface MyInterface // This is the non-generic interface.
{
object MyObject { get; set; }
}
public interface MyInterface<T> // This is the generic interface.
where T : MyOtherBaseClass
{
T MyObject { get; set; }
}
public abstract class MyBaseClass<T> : MyInterface, MyInterface<T> // This class implements both the non-generic and the generic interface.
where T : MyOtherBaseClass
{
public T MyObject { get; set; } // Implementation of the generic property.
object MyInterface.MyObject // Implementation of the non-generic property.
{
get { return MyObject; }
set { MyObject = (T)value; }
}
}
...
MyInterface baseObject; // The non-generic interface is used as base object.
baseObject = new MyImplementation(); // It is assigned an instance of MyImplementation which uses a generic base class.
object value = baseObject.MyObject;
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