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[英]How do you cast a vector of smart pointers to a constant vector that hold smart pointers that point to constants?
[英]Do you need to tell Smart Pointers when you are done with them
使用智能指針,是否仍然需要釋放/重置它們以確保釋放內存? 還是可以讓它們超出范圍?
類成員智能指針的行為是否有所不同-與釋放內存,懸空指針有關? 析構函數應該始終釋放這些變量嗎?
class Foo
{
public:
Foo()
{
myUPtr = std::unique_ptr<int>(new int);
mySPtr = std::shared_ptr<int>(new int);
}
~Foo()
{
// Should these smart pointers be released? Or will falling out of scope/deletion release the memory?
myUPtr.release();
mySPtr.reset();
}
private:
std::unique_ptr<int> myUPtr;
std::shared_ptr<int> mySPtr;
};
int main()
{
// When each of the below variables fall out of scope is there any difference in memory release?
Foo f;
std::unique_ptr<Foo> uFoo(new Foo);
std::shared_ptr<Foo> sFoo(new Foo);
std::unique_ptr<int> uPtr(new int);
std::shared_ptr<int> sPtr(new int);
// Will all these smart pointers be released automatically?
// No need to call .release()/.reset() on any member and non-member smart pointers?
return 0;
}
您是否仍需要釋放/重置它們以確保釋放內存?
沒有
還是可以讓它們超出范圍?
是
析構函數應該始終釋放這些變量嗎?
沒有
使智能指針如此智能和強大的原因之一是,您不再需要擔心手動管理內存。
僅供參考, std::unique_ptr::release
實際上將減輕智能指針的職責:它返回原始指針,然后您需要對其進行手動管理。
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