單元測試耦合方法

Question

在下面的示例中，如果無法設置aggregationInfo對象，如何為Deaggregate（）方法編寫單元測試？

public class Aggregator
{
    private AggregationInfo aggregationInfo;

    public List Aggregate(List objects)
    {
        //set aggregationInfo
    }
    public List Deaggregate(List aggregatedObjects)
    {
        //use aggregationInfo for the deagregation 
    }
}

Answer 1

我將通過調用Aggregate然后調用Deaggregate ，通過調用具有不同List的Aggregation並在這些情況下驗證Deaggregate中的預期行為來提供不同的方案

Answer 2

如果要確保僅對方法進行單元測試，則可以執行以下操作：

public class Aggregator
{
    private AggregationInfo aggregationInfo;

    private readonly IAggregator aggregator;
    private readonly IDeaggragator deaggragotor;

    public Aggregator(IAggregator aggregator, IDeaggragator deaggragotor)
    {
        this.aggregator = aggregator;
        this.deaggragotor = deaggragotor;
    }

    public List Aggregate(List objects)
    {
        this.aggregationInfo = aggregator.Aggregate(objects);
        return someListIDontKnowWhereYouGetThisFrom;
    }

    public List Deaggregate(List aggregatedObjects)
    {
        return deaggregator.Deaggregate(objects, this.aggregationInfo);
    }
}

然后，您對Aggregator的單元測試可以像這樣工作：

var systemUnderTest = new Aggregator(new MockAggregator(), new MockDeaggragator());

這將允許您驗證Aggregator將為IAggregator和IDeaggragotor提供正確的參數。

最后，您還可以在單​​獨的單元測試中測試RealDeaggragotor ，這可以滿足您的問題。

Answer 3

不確定為什么您的匯總器需要知道該信息，這不應該是匯總返回值的屬性嗎？

public static class Aggregator
{
    public static AggregatedList Aggregate(List objects)
    {
        // aggregate objects to aggregatedlist and set the aggregationInfo
    }

    public static List Deaggregate(AggregatedList aggregatedList)
    {
        // use info from the aggregatedList
    }
}

public class AggregatedList
{
    public AggregationInfo AggregationInfo { get; set; }
    public List AggregatedObjects { get; set; }
}